How did STATISTICS 1 go?

[sycho cj]

what was the answer for q7

 

[thementor]

permutations and combinations was tough answers wee 720 237 and 57

your answers are wrong.
720 is correct. The next two were 80, and 49

 

[Hassan Ali Abid]

was it harder than last years? cause that one was a tough one :/

It was far easier then that which came last year.

 

[A star]

yeahit was a tough one last year i regret doing the silly errors in last years S1 but seeing the tough time table gifted by cie i didnt give a retake and due to p3 am regretting it now

 

[Shadow]

your answers are wrong.
720 is correct. The next two were 80, and 49

Bro ur last answer is wrong as well 720 is correct though.. n i dun remember :/ i think i also got 80 to the second part.. even i got the third part wrong xD i got 98.. but it wasnt that simple.. wait for 24 hours to pass completely, then i will explain ya

 

[Shadow]

Damn the paper was easy cheesy!! but i m soo angry with myself i cudnt figure out the sol to q4, although it was soooo easy! did several ques like q4 at home; lekin CIE ka pressure.... -_-

 

[shah zaib]

your answers are wrong.
720 is correct. The next two were 80, and 49

i got 720, 60 and 49. And i think i got them right. How 80?

 

[samantha liyanage]

It was a good paper.
Just messed up the last 2 parts of permutations
hopefully it'll be around 38

 

[IGCSE13]

What was the mean and variance ?

 

[thementor]

Bro ur last answer is wrong as well 720 is correct though.. n i dun remember :/ i think i also got 80 to the second part.. even i got the third part wrong xD i got 98.. but it wasnt that simple.. wait for 24 hours to pass completely, then i will explain ya

lol dude. I asked my teacher. She told me it was 49

 

[thementor]

lol dude. I asked my teacher. She told me it was 49

the question stated repetition is allowed and less than and the numbers shkuld be less than 1000 and multiples of 5. so the last digit has onr possibility. and there were 7 no.s in total. since repetitions are allowed and it was a three digit no. 7x7 =49

 

[thementor]

i got 720, 60 and 49. And i think i got them right. How 80?

the question said b/w 3000 and 5000 and even no.s
the original no.given to u was 1345789.
for the no. To be even the last digit had two possiblities. The first digit could be 3 or 4, therefore 2 possibilities. It was a 4 digit no. So the two digits in the middle could be arranged in 5P2 ways.
total is 2 x 2 x 5P2 =80

 

[thementor]

What was the mean and variance ?

the mean was 11.7 and variance was 0.600

 

[SarahkAbdoon]

can we discuss the paper?

 

[Wolfgangs]

the question said b/w 3000 and 5000 and even no.s
the original no.given to u was 1345789.
for the no. To be even the last digit had two possiblities. The first digit could be 3 or 4, therefore 2 possibilities. It was a 4 digit no. So the two digits in the middle could be arranged in 5P2 ways.
total is 2 x 2 x 5P2 =80

Actually, there are three possibilities, 3 _ _ 4, 3 _ _ 8 and 4 _ _ 8. Since if 2 and 8 are at the end, then you will get an even number between 3000 and 5000

 

[A star]

the mean was 11.7 and variance was 0.600

finally good to seee u correcting others now buddy

 

[Mohammad Farzanullah]

the question stated repetition is allowed and less than and the numbers shkuld be less than 1000 and multiples of 5. so the last digit has onr possibility. and there were 7 no.s in total. since repetitions are allowed and it was a three digit no. 7x7 =49

u r forgetting that there could be 2 digits or single digit numbers also
so the answer is 57!

 

[thementor]

awww damn

 

[thementor]

Actually, there are three possibilities, 3 _ _ 4, 3 _ _ 8 and 4 _ _ 8. Since if 2 and 8 are at the end, then you will get an even number between 3000 and 5000

so you're saying 80 is not the answer. Seriously man!

 

[shah zaib]

People, where do you think will the A* be at? predictions? i believe it will be between 208-212 on 250. Anybody expecting an A*?