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Does any one remember the mass of mgso4? and laso what was the answer to the third part of enthalpy change ?
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I lost 1 mark here then..one mark for this statement and one mark for writing "according to markovnikov's rule.....(your answer here) ""
mass was 3.01 I guess.Does any one remember the mass of mgso4? and laso what was the answer to the third part of enthalpy change ?
ng to the markovnikoves rule any element is added to the carbon which already has maximum numbers of hydrogen. so I think it had something to with the negativity of bromine ?one mark for this statement and one mark for writing "according to markovnikov's rule.....(your answer here) ""
mine were 88kj-molmass was 3.01 I guess.
Answer to that is -94KJ/mol
so the heat transferred had nothing to with the mass of mgso4 only water were takenm
mine were 88kj-mol![]()
according to markovnikov's rule the bromine atom will attach to the carbon (one with the double bond) with less hydrogen and hydrogen from HBr to carbon with more hydrogen atoms.but accordi
ng to the markovnikoves rule any element is added to the carbon which already has maximum numbers of hydrogen. so I think it had something to with the negativity of bromine ?
mass of mgso4 was used to calculate moles .so
so the heat transferred had nothing to with the mass of mgso4 only water were taken
mass of mgso4 was used to calculate moles .
So this is it, I think many would loose marks on small stuff.according to markovnikov's rule the bromine atom will attach to the carbon (one with the double bond) with less hydrogen and hydrogen from HBr to carbon with more hydrogen atoms.
So this is it, I think many would loose marks on small stuff.
It was in question only.. 45g and temp was 11.8 maybemass of water and temperature changes?
mass of water want 50? or maybe I forgotIt was in question only.. 45g and temp was 11.8 maybe
It was 45 till I remember..mass of water want 50? or maybe I forgot
and what were the number of moles?It was 45 till I remember..![]()
0.025 what about you??and what were the number of moles?
0.025 what about you??[/QUOT
according to all the figures youve provided the answer should come 88 kj -mol![]()
That's the answer to the above part of the question it was 85accor
yup the sameaccor
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