How was Additional Mathematics Paper 4037/12

[M.Omar]

What were your answers to last question?

set of values of k?

 

[M.Omar]

Maybe 1390. I differentiated and equated it to zero. Then put the value in the equation to get minimum value. Correct?
And then i used second derivate to prove the minimum nature

What about That sketching absolute curve? What was k? I wrote k>3.125

Are there marks for steps?

yeah those were the steps for differentiation question..area 1390
and k>3.125
any other questions? to discuss

 

[Dark Destination]

Okay, let's review all the answers.

First question was proving identity. The answer was 2..

Then sets. The answers were 7, 5, 9...

The curve. I drew it, and reflected it in the x-axis. Points were 2,0 and -0.5,0 and 0,2
And also put the turning point as 0.75,3.125

Then K>3.125
I saw that from the graph, but also found the turning point as the working for this question.

Then combinations. 720, 240, 144, 9820?

Integration. I took intergral of the curve, with limits 0 and A. And then got two values for A, and chose the one below 1, pie/9 something?

And then differentiation. Proved the volume thing. And then 1390 and minimum..

Then, Circular measure. Proved angle. Then 48.7 perimeter, and then area was 100 something..

And then relative velocity, proved 10i + 10j using trignometric ratios? Thats what we were supposed to do?

Then, i got the position vector. Then in the next part, it was position vector after 1600 so we had to use the previous answer + speed*t
Then equated the position vectors to get 1380..

 

[Dark Destination]

So the paper was harder than previous ones? Or easier?

 

[sid2333]

What were your answers?

I had 9820 for the last part of combination, and 144 and 240 and 720 above that.

For relative velocity, my time was 1830 and t was 2.5.

And the value of A was pie/9 in that integration question. I didn't recheck ._.

value of a was pie/9 yes, i got the same. I also got 240 and 720, but not 144. IDK. what were the values of k. do u remember? I thought we needed to use discriminant for that (b2-4ac=0)

 

[Dark Destination]

value of a was pie/9 yes, i got the same. I also got 240 and 720, but not 144. IDK. what were the values of k. do u remember? I thought we needed to use discriminant for that (b2-4ac=0)

I used discriminant, and was getting -3.125 :/
It was a weird question. But i wrote the answer as k>3.125 and also calculated the turning point, to show it as working!

 

[sid2333]

Well, had two answers.
And the other previous two trignometric ones, were easy. I factorized, and equated them. Then calculated basic angle and stuff.

One of them was 270... but that was the only answer in that trignometric ratio.. right?

What about relative velocity?

30, 150, 270?

 

[Dark Destination]

yeah those were the steps for differentiation question..area 1390
and k>3.125
any other questions? to discuss

Was the combination answer 144?

 

[M.Omar]

Okay, let's review all the answers.

First question was proving identity. The answer was 2..

Then sets. The answers were 7, 5, 9...

The curve. I drew it, and reflected it in the x-axis. Points were 2,0 and -0.5,0 and 0,2
And also put the turning point as 0.75,3.125

Then K>3.125
I saw that from the graph, but also found the turning point as the working for this question.

Then combinations. 720, 240, 144, 9820?

Integration. I took intergral of the curve, with limits 0 and A. And then got two values for A, and chose the one below 1, pie/9 something?

And then differentiation. Proved the volume thing. And then 1390 and minimum..

Then, Circular measure. Proved angle. Then 48.7 perimeter, and then area was 100 something..

And then relative velocity, proved 10i + 10j using trignometric ratios? Thats what we were supposed to do?

Then, i got the position vector. Then in the next part, it was position vector after 1600 so we had to use the previous answer + speed*t
Then equated the position vectors to get 1380..

for velocity proved by using pyt theorem....K*(modulus 5i+12j)=26 so k=2 and thus veolity vector=2*(5i+12j)

 

[sid2333]

there was also another value

I used discriminant, and was getting -3.125 :/
It was a weird question. But i wrote the answer as k>3.125 and also calculated the turning point, to show it as working!

 

[Dark Destination]

30, 150, 270?

Yes, that was the first one. What about second?

 

[M.Omar]

Was the combination answer 144?

yeah but in trig question range of tht one variable was frm 0 to 180 for y and thus 270 cud not be incl

 

[M.Omar]

Yes, that was the first one. What about second?

no i think 0,101.3,180 or sth like tht was for first part?.....Look at ram 37 post in add maths thread...

 

[M.Omar]

So the paper was harder than previous ones? Or easier?

harder for me,a little abv standard to be precise

 

[sid2333]

did did u get the radius 25.23cm when equating dA/dr to 0?

What were the answers for A? In that integration. I got pie/9 something :/

And differentation? I got 1930 as the area, and minimum point. Had to use cosine rule in circular measure to prove theta angle. And then 48.7 perimeter, and then what about area?[/quote

 

[Dark Destination]

there was also another value

How can there be two values?

 

[Dark Destination]

yeah but in trig question range of tht one variable was frm 0 to 180 for y and thus 270 cud not be incl

What? Was 270 coming in that question? Or was 270 there in second one?

 

[M.Omar]

How can there be two values?

View attachment 45240

since it was in factorised form the turning point cud be fig by adding x coordinates and div by 2) and later process carry on...was it abs necessary to use discrimanant

 

[sid2333]

i

Maybe 1390. I differentiated and equated it to zero. Then put the value in the equation to get minimum value. Correct?
And then i used second derivate to prove the minimum nature

What about That sketching absolute curve? What was k? I wrote k>3.125

Are there marks for steps?

i think we needed to find the discriminant. There were two values, one was yours and other i dnt remember

 

[M.Omar]

What? Was 270 coming in that question? Or was 270 there in second one?

nope 270 was not in either coz both had single variable with range 0<x<180