- Messages
- 19
- Reaction score
- 8
- Points
- 3
No it went like this:
60cm3 of some concentration of naoh reacted with the gases. It was 0.03 moles i think. And the excess was titrated with H+ giving 0.0054 moles. So the moles that rwacted with the gases were 0.03-0.0054
60cm3 of some concentration of naoh reacted with the gases. It was 0.03 moles i think. And the excess was titrated with H+ giving 0.0054 moles. So the moles that rwacted with the gases were 0.03-0.0054