how was M1 42

[leadingguy]

It was a 100 time better than the june 2012 ones . Thank god ! Thank you Cambridge ^^
Hope the nest ppers will be easy too

next ???? p3 ??

 

[InnocentAngel]

next ???? p3 ??

Wup p3 !
Let's work hard for it!! It's 75% of the syllabus , so if 1 mark is lost it turns out to be 2 to 3 times more than when we lose 1 mark in p4 .
Best of luck to you all!!

 

[leadingguy]

Wup p3 !
Let's work hard for it!! It's 75% of the syllabus , so if 1 mark is lost it turns out to be 2 to 3 times more than when we lose 1 mark in p4 .
Best of luck to you all!!

no no !!! I donot think ?? it contributes 30%
P1 30%
p3 30%
s1 20%
m1 = 20% m I w rong ??

 

[Adhiraj Shinde]

yes about the last part itself

 

[Adhiraj Shinde]

dude no way 25.2 for he u th ,ax speedi s 6.4

maybe so,i said coz all of us in our centre got the same answer,it was unanimous that is why. 6.4 could also be rite

 

[Z.S.M]

i think dat coefficient of friction was "0.9"

yeah

 

[Amy Bloom]

this senior o mine had an E in stats and A's in all the other components. He had an overall A*.

Honestly speaking, i remained like this: for a while in front of the computer screen. Are you sure of that???? that's weird!
Then, the stats paper was it supposed to be easy for your senior?

 

[Amy Bloom]

Wup p3 !
Let's work hard for it!! It's 75% of the syllabus , so if 1 mark is lost it turns out to be 2 to 3 times more than when we lose 1 mark in p4 .
Best of luck to you all!!

Let me clarify this to you.
Paper 1 - 75 marks - 30 %
Paper 3 - 75 marks - 30%
Paper 4 - 50 marks - 20%
Paper 6 - 50 marks - 20%

 

[leadingguy]

Let me clarify this to you.
Paper 1 - 75 marks - 30 %
Paper 3 - 75 marks - 30%
Paper 4 - 50 marks - 20%
Paper 6 - 50 marks - 20%

u too giving p3 ???

 

[mhalvi]

n was q 4 answer 39N n diection 22.6'AC from x direction ?

absolutely correct!!

 

[Amy Bloom]

u too giving p3 ???

Yup!

 

[doorman1995]

absolutely correct!![/quote
thanks god n wht abt last ques last part?

 

[mhalvi]

what was your answer?I dont remember the exact figure but I remember the way I did it...at A displacement would be zero so as we had earlier found displacement equation we had to equate it to zero and find the value of t and then substitue it into the velocity equation to get the velocity, I hope you get it

 

[doorman1995]

hehe no problem
I think it was something 0.693, 6 divided by 5under root 3

yup i got the same and wht abt last ques last part?

 

[mhalvi]

what was your answer?I dont remember the exact figure but I remember the way I did it...at A displacement would be zero so as we had earlier found displacement equation we had to equate it to zero and find the value of t and then substitue it into the velocity equation to get the velocity, I hope you get it

yup i got the same and wht abt last ques last part?

 

[doorman1995]

what was your answer?I dont remember the exact figure but I remember the way I did it...at A displacement would be zero so as we had earlier found displacement equation we had to equate it to zero and find the value of t and then substitue it into the velocity equation to get the velocity, I hope you get it

well i remember the distance OA was 216m for b part it was like -0.72m/s2 n for third part iam confused

 

[mhalvi]

well i remember the distance OA was 216m for b part it was like -0.72m/s2 n for third part iam confused

first 2 are correct,I dont remember the last part

 

[doorman1995]

first 2 are correct,I dont remember the last part

well for the third one yea it was for 2 marks i simply applied distance formula v2=u2+2as cs we had distance 216 final velocity 0 a=-0.72 and calculated v

 

[Pals_1010]

first 2 are correct,I dont remember the last part

You got something like 25.6 m/s for the last part?

 

[mhalvi]

You got something like 25.6 m/s for the last part?

yep...if I remember correctly