- Messages
- 50
- Reaction score
- 5
- Points
- 18
the original system, because it said its back at 297 K
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i think 40 if i am not mistakenWhat was the rise in temp?
How did u calculate it?i think 40 if i am not mistaken
How did u calculate it?
How did u calculate it?
How did u calculate it?
Got it. ThanksYaa its 40..
0.190 mol produces 95j
1 mol produces 500j
Den u knw dere is a change of 1K fr 12.5j so fr 500 j hw much.. xactly 40K.
I cnt remember.. wat did u gt?Got it. Thanks
What about Capacitance? What was it? In pF.
5.00 x 10^ something.I cnt remember.. wat did u gt?
it was 50Got it. Thanks
What about Capacitance? What was it? In pF.
Damn. I messed up in conversions :Lit was 50
i am damm sure it was only 50p ans will will 50 only
i wrote different reflections on different bounderies will determine thickness of corresponding media......i messed up last part of photon question cuz i didnt understand itcan any one explain why difference in Z1 and Z2 was important
i dont know but i wrote change in internal energy ws zero, there was a rise in temp cause workdone ws negative so by equation it ws 0 = Q - W therefore W = Q......ohh i hope its right !!!!the gas system in question 2 part (b) doing 120J of work, which gas system does it refer to? Heated one or original gas system?
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