How was physics 9702 p41 ???

[Ahmed kooheji]

I personally found it really good .. what do u think the threshold for A will be ? I predict it will be more than 65 .. and can anyone remember some of the answers?

 

[ThePacifics]

I found it okay. there were tricky parts. what did you get for capacitor? and the moles answer and the graph and the Activity stuff. i need to recheck my answerssksksk

 

[Ahmed kooheji]

Well, I’ll tell u what I remember.. alright so for the last page .. activity was 3.6*10^4. And the decay constant was 4.1 *10^-4 ... and graph? U mean the force and time?? I got a sinusodial graph with peak current at 7.2A and time period 0.05s

 

[ThePacifics]

are you sure the answers are correct?
what method did u apply for that Activity thing. I put N= No e^ lambta t and had found the half life and stuff since it said ' refer to the graph'

 

[Ahmed kooheji]

Force is directly proportional to current

 

[Ahmed kooheji]

About the activity .. ur method is correct

 

[armeena]

It was really shitty. I got the same answers as you for my activity, i think. as for the graph, was it a sin graph or a cosine graph?

 

[Ahmed kooheji]

Sin graph

 

[armeena]

for the capacitors, was Q=it just the current multiplied by 1 or were we supposed to use the frequency? what about the electric sphere thing's second part?

 

[Ahmed kooheji]

Yes it was just Q multiplied by 1 sec .. and for the electric field the answer was 3Q (for ten second part )

 

[Ahmed kooheji]

What do u guys think tbe threshold for A will be ?

 

[armeena]

ok, here's all my questions:
1) were the planets in equilibrium?
2) what happened to the current as a second capacitor was added?
3) for calculating the force for the length given in the second part, did you use F=BIL or BILsin theta (like multiplied L by sintheta again?)
4) for the x-ray intensity question, were we supposed to multiply both the e^-Mo? if you can remember what the contrast was, that'd be great.
5) what direction was the force on the magnet?

That's all for now. lol sorry, i did say it was shit

Yes it was just Q multiplied by 1 sec .. and for the electric field the answer was 3Q (for ten second part )

how did you get 3Q loool.

What do u guys think tbe threshold for A will be ?

maybe 60+?

 

[ThePacifics]

i made a sin graph with 0.05 time period but i think my force is wrong i hope i'll get marks for the rest lol?

 

[ThePacifics]

ok, here's all my questions:
1) were the planets in equilibrium?
yes because the planets and the star exerted equal and opposite forces on each other ?
2) what happened to the current as a second capacitor was added?
charge is same in series capacitor so no diff in ammeter reading?
3) for calculating the force for the length given in the second part, did you use F=BIL or BILsin theta (like multiplied L by sintheta again?)
yes because original formula is BILsin theta so sin theta and sin theta got cancelled by that 60 thing.
4) for the x-ray intensity question, were we supposed to multiply both the e^-Mo? if you can remember what the contrast was, that'd be great.
i think i got this wrong
5) what direction was the force on the magnet?
there wasnt no force on magnet it was on wire is what i wrote sigh because the wire is going to experience force?

 

[Ahmed kooheji]

ok, here's all my questions:
1) were the planets in equilibrium?
2) what happened to the current as a second capacitor was added?
3) for calculating the force for the length given in the second part, did you use F=BIL or BILsin theta (like multiplied L by sintheta again?)
4) for the x-ray intensity question, were we supposed to multiply both the e^-Mo? if you can remember what the contrast was, that'd be great.
5) what direction was the force on the magnet?

That's all for now. lol sorry, i did say it was shit





how did you get 3Q loool.



maybe 60+?

Aight .. to get 3Q (additional charge) u first have to find the charge when the sphere has a radius of 52cm which is 6*10^-6 C and the Q (sphere with 28cm radius) was 1.5*10^-6 so to find the additional charge u have to subtract 6-1.5 which is 4.5 *10^-6. And then divide it by Q (which is 1.5*10^-6) so you’ll get 3

 

[ThePacifics]

i

Aight .. to get 3Q (additional charge) u first have to find the charge when the sphere has a radius of 52cm which is 6*10^-6 C and the Q (sphere with 28cm radius) was 1.5*10^-6 so to find the additional charge u have to subtract 6-1.5 which is 4.5 *10^-6. And then divide it by Q (which is 1.5*10^-6) so you’ll get 3

just did the subtraction idk where the 3Q came from?

 

[Ahmed kooheji]

They said in terms of Q .. how much more charge is required .. it’s 3 times the original charge so 3Q

 

[ThePacifics]

They said in terms of Q .. how much more charge is required .. it’s 3 times the original charge so 3Q

i think i'll get only one mark cut because i did the rest like the subtraction and stuff?

 

[Ahmed kooheji]

I think so

 

[ThePacifics]

what did u get for number of atoms in helium thing