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Inshallah!so ur expecting an a* overall? well done if u do man
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Inshallah!so ur expecting an a* overall? well done if u do man
i didnt get thatQuestion No.1
change in kinetic energy as far I could remember was 1.0 x 10^8 J
Change in P.E was something like in magnitude of 10 ^-17 J
and the linear speed decreased because of loss in K.E from calculations ?
so what were your answers?I didn't get that either.
My Kinetic energy change was positive and I said the velocity increases as V^2 is proportional to Kinetic energy.
Did any1 inbox it to u? Pls inbox it to me a well!shit, should have scored full marks for such a paper!! :"( something went wrong for two parts. Btw, can anyone inbox me a msg of how the graph for the opamp comparator should be?
Derive using gravational force = Cent. Force then x1/2what was the attenuation per length? , what was the graph like for comparator? , how did u derive the expression for K.e in 1st or second question. was it simply equating mv^2/ 4 = gmm/r^2 .......and then later obtaining the same expression? , which area of the rectangle in the magnetic field question you shaded for the electron upper face or lower face ? , , , what were the reasons for particle effect etc for that last question of quantum?
kindly share ur answers apart from predicting stupid gt :|
Nopes :'(Did any1 inbox it to u? Pls inbox it to me a well!
what was your answer for number of bits? i got a very huge no!
i think i got 3.81 x 10^8something like 2.39 or 2.40 x 10^8
Yes the K.E was 9.something x 10^7 Jwas the k.e 9 into 10^7 j something?
Can you tell me how were me suppose to do that question ?something like 2.39 or 2.40 x 10^8
Yes the K.E was 9.something x 10^7 J
The graph for the comparator was a square curve with maximum and minimum amplitude at the input supply.
The attenuation per length was 17dB/Km
The face was not upper or lower it was the side of the rectangle which was into the page.
The reasons were:
1- Increasing the intensity doesnt increase number of electron emitted from the surface
2- One photon can interact with and hence exchange energy with only one electron. There is a one-to-one interaction.
3- If the frequency is below the threshold frequency there will be no emission of electron.
Do you remember the given data for the bits question?how did you do the 'bit' question?
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