How was Physics P42

[Mukit-ul Islam]

so ur expecting an a* overall? well done if u do man

Inshallah!

 

[Mukit-ul Islam]

Question No.1
change in kinetic energy as far I could remember was 1.0 x 10^8 J
Change in P.E was something like in magnitude of 10 ^-17 J
and the linear speed decreased because of loss in K.E from calculations ?

i didnt get that

 

[manu94]

I didn't get that either.
My Kinetic energy change was positive and I said the velocity increases as V^2 is proportional to Kinetic energy.

 

[creative22]

I didn't get that either.
My Kinetic energy change was positive and I said the velocity increases as V^2 is proportional to Kinetic energy.

so what were your answers?

 

[manu94]

I don't remember exactly. Kinetic energy was positive and potential was negative is all that I remember.

 

[confused123]

was the k.e 9 into 10^7 j something?

 

[confused123]

what was the attenuation per length? , what was the graph like for comparator? , how did u derive the expression for K.e in 1st or second question. was it simply equating mv^2/ 4 = gmm/r^2 .......and then later obtaining the same expression? , which area of the rectangle in the magnetic field question you shaded for the electron upper face or lower face ? , , , what were the reasons for particle effect etc for that last question of quantum?

kindly share ur answers apart from predicting stupid gt :|

 

[xyz!]

shit, should have scored full marks for such a paper!! :"( something went wrong for two parts. Btw, can anyone inbox me a msg of how the graph for the opamp comparator should be?

Did any1 inbox it to u? Pls inbox it to me a well!

 

[W-inx]

what was the attenuation per length? , what was the graph like for comparator? , how did u derive the expression for K.e in 1st or second question. was it simply equating mv^2/ 4 = gmm/r^2 .......and then later obtaining the same expression? , which area of the rectangle in the magnetic field question you shaded for the electron upper face or lower face ? , , , what were the reasons for particle effect etc for that last question of quantum?

kindly share ur answers apart from predicting stupid gt :|

Derive using gravational force = Cent. Force then x1/2

I did get change in kinetic energy as far I could remember was 1.0 x 10^8 J But then after retrying i got another value.

 

[W-inx]

Who remembers the value of GM?? it was 4. something i forgot :S

 

[akshay.RONALDO]

Did any1 inbox it to u? Pls inbox it to me a well!

Nopes :'(

 

[Mukit-ul Islam]

what was your answer for number of bits? i got a very huge no!

 

[Pals_1010]

what was your answer for number of bits? i got a very huge no!

something like 2.39 or 2.40 x 10^8

 

[Mukit-ul Islam]

something like 2.39 or 2.40 x 10^8

i think i got 3.81 x 10^8

 

[manu94]

was the k.e 9 into 10^7 j something?

Yes the K.E was 9.something x 10^7 J
The graph for the comparator was a square curve with maximum and minimum amplitude at the input supply.
The attenuation per length was 17dB/Km
The face was not upper or lower it was the side of the rectangle which was into the page.

The reasons were:

1- Increasing the intensity doesnt increase number of electron emitted from the surface
2- One photon can interact with and hence exchange energy with only one electron. There is a one-to-one interaction.
3- If the frequency is below the threshold frequency there will be no emission of electron.

 

[rose1700]

Nobody's answers are matching
I got change in Ek 1.0 x 10 ^8
I did it on a scientific calculator just put the values in the equation cant get it wrong.
And attenuation was 52dB/Km

 

[rose1700]

something like 2.39 or 2.40 x 10^8

Can you tell me how were me suppose to do that question ?

 

[Taci12]

Yes the K.E was 9.something x 10^7 J
The graph for the comparator was a square curve with maximum and minimum amplitude at the input supply.
The attenuation per length was 17dB/Km
The face was not upper or lower it was the side of the rectangle which was into the page.

The reasons were:

1- Increasing the intensity doesnt increase number of electron emitted from the surface
2- One photon can interact with and hence exchange energy with only one electron. There is a one-to-one interaction.
3- If the frequency is below the threshold frequency there will be no emission of electron.

Besides the comparator, I got the same answers! For the reasons, there is also the fact that the photo-current or rate of emission of electrons increases linearly with increasing intensities of incident radiation.

 

[Mukit-ul Islam]

how did you do the 'bit' question?

 

[Taci12]

how did you do the 'bit' question?

Do you remember the given data for the bits question?