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The paper was either TOO long for 1 hour or 1 hour is TOO short for the paper... :/
I cudnt draw the graph
graph??????
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The paper was either TOO long for 1 hour or 1 hour is TOO short for the paper... :/
I cudnt draw the graph
1570 Ni remember one of the question ask what is the wavelength
neway, what u guys got for the Tension T??
2.0 joulesAnd change in PE?
gradeint was halfguys for the Young Modulus graph u have to draw, the gradient is twice the given graph right?
Also, if you'd help me with one of the other answers that'd be nice,Just so u know E=mc2 is in A2 but yeah ur answer is right.
u just have to calculate initial KE... final KE was 0... and i got 2.0 for PEmy KE was 1. something and PE was 0.44 for ke it was simple just subtract two kinetic energies! for pe find the rebound height of the ball and use mgh
650 + 450gsin12How did u ppl gt d tension in d string nywy??
What u said there,i didnt understand how?Also, if you'd help me with one of the other answers that'd be nice,
its regarding uncertainty value.. there were 4 quantities given "v/t", "P", "l", "r".. in the equation it was r^4 so we multiply the uncerainty by 4.. BUT..
we are suppose to take the inverse of "v/t" so uncertainty value of this quantity will be multiplied by -1 but I, by mistake forgot to multiply -1 and hence I ended up adding all the values together..
besides that one thing, my method was correct will I get marks out out of 3?
Can anyone plz explain the method to find K.E and P.E2.0 joules
didn't you solve the uncertainty question ?What u said there,i didnt understand how?
hahahahah..............wrong..!!!!! lambda was obviously 68 cm...convert to metres.......= .68m....the 340/0.68....= 500Hz.....simple as that........if any one got answerlike 1000 means he took lamba has 38 which was wrong and the trick in the ques which apparently will loose 2 marks out of 3ITS 1000Hz for sure.....people who r telin 500Hz made mistake in cm to m conversion.....ma whole class got 1000hz ...abt 56 students...LOL...still 500hz people thnk its wrng??lmao
you are correct...dont worry, no need to take inverse, you are just dividing by 1.2 * 10^-6 on other side.....so take into account the simple uncertainti +-0.01.....no need for minus signAlso, if you'd help me with one of the other answers that'd be nice,
its regarding uncertainty value.. there were 4 quantities given "v/t", "P", "l", "r".. in the equation it was r^4 so we multiply the uncerainty by 4.. BUT..
we are suppose to take the inverse of "v/t" so uncertainty value of this quantity will be multiplied by -1 but I, by mistake forgot to multiply -1 and hence I ended up adding all the values together..
besides that one thing, my method was correct will I get marks out out of 3?
Mr lamao distance between two nodes was 0.34 m and in a STATIONARY wave distance between two nodes is lambda/2=0.34 m.Now prove how i am wrong
i think it might b 35...Fuu.. I meant paper 22
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