How was physics paper 33

[mujtabashahnawaz]

noo its (bigger k - smallerk) divde by average of da 2 ks into 1oo...

No dude u are informed wrong, my sir told me this formula !

 

[leosco1995]

Actually if its less than twenty percent then there is a direct relationship

Yes exactly, so it depends on your percentage difference between the values of k, so there is no definite answer, it just depends on your own values.

 

[thunderingthunder]

My gradient was 0.11:S

 

[Knight]

i used the equation to find the y-intercept as my graph didn't start with the x-axis at 0......

 

[JD REBORN]

The graph didnot have a negative gradient for the love of GOD.

 

[Knight]

OH GOD.....i am so confused about the gradient

 

[fathimaash]

No dude u are informed wrong, my sir told me this formula !

oh really dis is da equation we hv been using for all our practicals... nd my teacher said she has got dis from da mark scheme nd xaminars report....

 

[Hertz]

i found out (k1-k2)/avg k *100 = 25% then i found out max permissible error which was 36% diff is 36-25=11 so it MAY support they said if u find out max permissible error...u can write "may support" dont know if its right or not

 

[Casablanca]

My gradient was positive, but I didn't have any trend in the values either. I think I did well, but I'm not sure. Oh well, e.c.f will set us straight, hopefully.

 

[Knight]

e.c.f will be allowed for the gradient and the values for P and Q in the last part.

 

[robotic94]

hey what my sir told me was less than 10 % :O

 

[Knight]

hey what my sir told me was less than 10 % :O

i think it's less than 20%........

 

[fathimaash]

i think it's less than 20%........

ya less than 20%

 

[code11]

ya less than 20%

cud anyone tell me about the GT of this paper ? :O
31 out 40?

 

[aom]

My gradient was 0.11:S

0.011 or 0.11??? a big difference

 

[aom]

cud anyone tell me about the GT of this paper ? :O
31 out 40?

28

 

[mujtabashahnawaz]

cud anyone tell me about the GT of this paper ? :O
31 out 40?

31 i think

 

[aom]

my gradient was -.00125.......don't know the exact value.

just remove the negative sign and u r correct LOL np they will conc. on your teqnique of drawing graphs ..

 

[aom]

The gradient had to be positive. Confirmed. Mine was 0.172 and I used grams and metres. But then again, I might be wrong.

i think u forgot to add a zero !!! o.o172 am i right??

 

[thunderingthunder]

0.011 or 0.11??? a big difference

0.11..