How was your paper 4 of Math ?????

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raysonzaffar

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paper 580/42
cake stuff area.........59.9cm2
nxt page simultaneous equation..........$0.85.... &.....$0.55
the linear programming....least possible cost for 20 trees was.........$145.....co-ordinates ( 9,11)
probablity.............9/14............and 14/25,,,,,,,,,,,,,,,,,,,,(i am not sure about the real values)
the question right after the cake one .........length AD of da 2 triangles...............is 37.9 cm
correlation was poitive,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,nd da marks were either 22 or 24 i dont reallly noe !!!
this is wht i did...........n got it chkd with my frnz..............i dont confidently say tht its ryt but i feel so !!!!!!!!!!!!!!!!!!!!!!!!!!!
 
Zico Sakr

Zico Sakr

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I'm just happy cuz we're done with maths!!!!!!!!!!!!
and I hope we finish the rest of our exams safely so that I can dance all night!
 
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nolife4now

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raysonzaffar said:
paper 580/42
cake stuff area.........59.9cm2
nxt page simultaneous equation..........$0.85.... &.....$0.55
the linear programming....least possible cost for 20 trees was.........$145.....co-ordinates ( 9,11)
probablity.............9/14............and 14/25,,,,,,,,,,,,,,,,,,,,(i am not sure about the real values)
the question right after the cake one .........length AD of da 2 triangles...............is 37.9 cm
correlation was poitive,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,nd da marks were either 22 or 24 i dont reallly noe !!!
this is wht i did...........n got it chkd with my frnz..............i dont confidently say tht its ryt but i feel so !!!!!!!!!!!!!!!!!!!!!!!!!!!
Click to expand...


every things correct
 
salvatore

salvatore

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Guys listen up! There may be no one in this thread who has used a different approach to the chocolate cream question.. here’s mine..
When finding the curved S.A (using perimeter x length), it includes the two rectangles at the sides. So you had to find the area of the two rectangles & subtract it from the curved S.A. This will find the area of the CURVED part. Then, add the area of the top sector to that of the curved part. The answer was around 202 – 203, nt sure! What do you say.. can this be right??
 
IGCSE O/L student

IGCSE O/L student

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salvatore said:
Guys listen up! There may be no one in this thread who has used a different approach to the chocolate cream question.. here’s mine..
When finding the curved S.A (using perimeter x length), it includes the two rectangles at the sides. So you had to find the area of the two rectangles & subtract it from the curved S.A. This will find the area of the CURVED part. Then, add the area of the top sector to that of the curved part. The answer was around 202 – 203, nt sure! What do you say.. can this be right??
Click to expand...
i dnt knw! :confused:
 
P

phantom

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salvatore said:
Guys listen up! There may be no one in this thread who has used a different approach to the chocolate cream question.. here’s mine..
When finding the curved S.A (using perimeter x length), it includes the two rectangles at the sides. So you had to find the area of the two rectangles & subtract it from the curved S.A. This will find the area of the CURVED part. Then, add the area of the top sector to that of the curved part. The answer was around 202 – 203, nt sure! What do you say.. can this be right??
Click to expand...
I am sorry to say, your approach is a little off here, if you use the cylinder's equation to find the curved surface area it will give you ONLY THE CURVED SURFACE AREA
 
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