How was your paper 4 of Math ?????

[Lostsoul]

yes, dats ryt.

Now I doubt my answer

 

[phantom]

Now I doubt my answer

Just forget about it and focus on whats next

 

[IGCSE O/L student]

Now I doubt my answer

yes, dnt wry. u may score sum marks 4 ur workin.

 

[Lostsoul]

You got it Wrong??

Seems like

 

[Lostsoul]

Just forget about it and focus on whats next

Okayy

 

[Lost_Life]

Hey guys.. the chocolate cream question.. who got 203??

i got 210

 

[Mrskeptikal]

did anyone do 42 here?

I did paper 42 lets compare our answers, give me your email or inbox me what u think ur uncertain about. Please check my thread out ive posted some of my answers there

 

[Lost_Life]

CAN ANYONE TELL ME HOW MANY MARKS WAS THE LAST INEQUALITY QUESTION FOR?

2

 

[IGCSE O/L student]

i got 210

i got 59.9

 

[Lost_Life]

i got 59.9

 

[David Hussey]

guys frgt abt it and concentarte on the nxt exam!!

 

[Lost_Life]

guys frgt abt it and concentarte on the nxt exam!!

um... can't

 

[David Hussey]

u keep thinking abt it...GOd forbid....u may not fair well in the next exam!!

 

[raysonzaffar]

paper 580/42
cake stuff area.........59.9cm2
nxt page simultaneous equation..........$0.85.... &.....$0.55
the linear programming....least possible cost for 20 trees was.........$145.....co-ordinates ( 9,11)
probablity.............9/14............and 14/25,,,,,,,,,,,,,,,,,,,,(i am not sure about the real values)
the question right after the cake one .........length AD of da 2 triangles...............is 37.9 cm
correlation was poitive,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,nd da marks were either 22 or 24 i dont reallly noe !!!
this is wht i did...........n got it chkd with my frnz..............i dont confidently say tht its ryt but i feel so !!!!!!!!!!!!!!!!!!!!!!!!!!!

 

[Zico Sakr]

I'm just happy cuz we're done with maths!!!!!!!!!!!!
and I hope we finish the rest of our exams safely so that I can dance all night!

 

[nolife4now]

paper 580/42
cake stuff area.........59.9cm2
nxt page simultaneous equation..........$0.85.... &.....$0.55
the linear programming....least possible cost for 20 trees was.........$145.....co-ordinates ( 9,11)
probablity.............9/14............and 14/25,,,,,,,,,,,,,,,,,,,,(i am not sure about the real values)
the question right after the cake one .........length AD of da 2 triangles...............is 37.9 cm
correlation was poitive,,,,,,,,,,,,,,,,,,,,,,,,,,,,,,nd da marks were either 22 or 24 i dont reallly noe !!!
this is wht i did...........n got it chkd with my frnz..............i dont confidently say tht its ryt but i feel so !!!!!!!!!!!!!!!!!!!!!!!!!!!

every things correct

 

[IGCSE O/L student]

um... can't

u hv 2! or else u wont b able 2 concentrate on all ur upcumin xams. hu knws if our ans is correct. ur may b ryt. so jst luk on da bright side of it n cheer up!

 

[salvatore]

Guys listen up! There may be no one in this thread who has used a different approach to the chocolate cream question.. here’s mine..
When finding the curved S.A (using perimeter x length), it includes the two rectangles at the sides. So you had to find the area of the two rectangles & subtract it from the curved S.A. This will find the area of the CURVED part. Then, add the area of the top sector to that of the curved part. The answer was around 202 – 203, nt sure! What do you say.. can this be right??

 

[IGCSE O/L student]

Guys listen up! There may be no one in this thread who has used a different approach to the chocolate cream question.. here’s mine..
When finding the curved S.A (using perimeter x length), it includes the two rectangles at the sides. So you had to find the area of the two rectangles & subtract it from the curved S.A. This will find the area of the CURVED part. Then, add the area of the top sector to that of the curved part. The answer was around 202 – 203, nt sure! What do you say.. can this be right??

i dnt knw!

 

[phantom]

Guys listen up! There may be no one in this thread who has used a different approach to the chocolate cream question.. here’s mine..
When finding the curved S.A (using perimeter x length), it includes the two rectangles at the sides. So you had to find the area of the two rectangles & subtract it from the curved S.A. This will find the area of the CURVED part. Then, add the area of the top sector to that of the curved part. The answer was around 202 – 203, nt sure! What do you say.. can this be right??

I am sorry to say, your approach is a little off here, if you use the cylinder's equation to find the curved surface area it will give you ONLY THE CURVED SURFACE AREA