IGCSE Chemistry Revision Guide | According to syllabus

[rjcooo1]

Condensation polymerisation is the process when two monomers join together to form a polymer but while joining up, the group of HCl/H2O is removed.
Check page 95 for the image

wat i didnt understand was the second picture in pg95

 

[rjcooo1]

Formula for alcohol's: CnH2n+1OH

Thanks Dani ............. the same applies for carboxylic acid but with different functional groups rite?

 

[rjcooo1]

Oops, CnH2n+1
Silly typo

Thank you too

 

[rjcooo1]

wat i didnt understand was the second picture in pg95

Can u pls explain it if possible?

 

[Dani222]

Thanks Dani ............. the same applies for carboxylic acid but with different functional groups rite?

Yup same thing
CnH2n+1COOH
You're welcome

 

[wooowooowoo]

wat i didnt understand was the second picture in pg95

Haha alright. I'll explain it here
H-O-O=C-[]-C=O-O-H + H-O-[]-O-H
You see the H+H at the ends?
They will get removed together with 1 O to form H2O
-O-O=C-[]-C=O-O-[]-O- + O-H-O

 

[rjcooo1]

Haha alright. I'll explain it here
H-O-O=C-[]-C=O-O-H + H-O-[]-O-H
You see the H+H at the ends?
They will get removed together with 1 O to form H2O
-O-O=C-[]-C=O-O-[]-O- + O-H-O

Owww so the H2O is not shown after they combine thanks

 

[wooowooowoo]

Owww so the H2O is not shown after they combine thanks

I'll explain it properly to you tomorrow with more examples, right now I've to go.
Sorry and good night

 

[rjcooo1]

I'll explain it properly to you tomorrow with more examples, right now I've to go.
Sorry and good night

Goodnight

 

[Alla' Abu-Sultaneh]

I CAN SEE THE LIGHT! Thank you for the notes!

 

[сᴏᴏʟ сяуѕтᴀʟѕ]

Yup same thing
CnH2n+1COOH
You're welcome

Assalam-o-alaikum wr wb...
this formula doesn't work it is better to 'make' it in order to find the molecular formula...
BCOZ the C in "COOH" also counts in " Cn H2n+1 " as the molecular formula for Methane is HCOOH but according to this formula it is
CH3COOH

 

[Dani222]

Assalam-o-alaikum wr wb...
this formula doesn't work it is better to 'make' it in order to find the molecular formula...
BCOZ the C in "COOH" also counts in " Cn H2n+1 " as the molecular formula for Methane is HCOOH but according to this formula it is
CH3COOH

so .. what formula to use?

 

[wooowooowoo]

Assalam-o-alaikum wr wb...
this formula doesn't work it is better to 'make' it in order to find the molecular formula...
BCOZ the C in "COOH" also counts in " Cn H2n+1 " as the molecular formula for Methane is HCOOH but according to this formula it is
CH3COOH

Methane is CH4

Methanoic acid is HCOOH.
This group is an exception where n=1 starts with Eth and NOT Meth.

 

[ZainH]

These notes > My textbook

How did I not see this thread before D:

 

[wooowooowoo]

These notes > My textbook

How did I not see this thread before D:

Organic chemistry will be improved tomorrow. People are having difficulty with it, it seems.

 

[ZainH]

Organic chemistry will be improved tomorrow. People are having difficulty with it, it seems.

Hm all right, I'll be sure to check that section out tomorrow!
Great job guys ThatReallyReallyWeirdDude

 

[сᴏᴏʟ сяуѕтᴀʟѕ]

so .. what formula to use?

actually this doesn't have any proper formula...in the chemistry 'revision guide' also it is mentioned that it is better to draw the molecular formula rather than using a formula...

OR another solution, as mentioned by wooowooowoo that learn it for methane, and for others 'subtract' one 'carbon' atom...for instance...if it is butane...you will take the n as 3 NOT 4...hope you get what i am trying to say?

 

[ThatReallyReallyWeirdDude]

Hm all right, I'll be sure to check that section out tomorrow!
Great job guys ThatReallyReallyWeirdDude

lol I only did Sulphur & Reversible reactions xD Credit goes to wooowooowoo

 

[ZainH]

lol I only did Sulphur & Reversible reactions xD Credit goes to wooowooowoo

Lol still counts!
But seriously, wooowooowoo you don't understand how many grades you've saved xD

 

[ThatReallyReallyWeirdDude]

Hmm
Could use:
C(n-1)H(2n-1)COOH
This way, if it's methanoic where n=1:
C0H1COOH=HCOOH
Works?
Ethanoic Acid:
C(2-1)H(4-1)COOH=CH3COOH
Propanoic Acid: (n=3)
C(3-1)H(6-1)COOH=C2H5COOH =CH3CH2COOH
EDIT: I just made this now so test if it works before just using.