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O/N -2006 -p4 --- 4 f(ii) ...do v hav 2 do by the ratio proportion method?
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You should have already found the scale factor to be 2.http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_23.pdf 17(b) how do u solve it? and for the map sizes and actual size and stuff .. What formula is used?
7ci. f(x)=2: Draw the line y=2 on the grid and find the intersection between y=2 and f(x).Can u plz solve Q7,c and d of oct/nov/10 v42
Do you mean the gradient question? This has nothing to do with ratio/proportion.O/N -2006 -p4 --- 4 f(ii) ...do v hav 2 do by the ratio proportion method?
This is too much for me to do and I'm not going to draw the graphs for you.
plzz answer the question 5a in the following paper:
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w12_qp_41.pdf
thnaks alot for the help but 1 small doubt for 7,d i made a line on y=5X but there is only one point intersecting with it can u explain a bit plz7ci. f(x)=2: Draw the line y=2 on the grid and find the intersection between y=2 and f(x).
7cii. Find any value of k such that when you draw y=k on the grid, there are three intersection points with the curve f(x).
7d. Draw the line y=5x on your grid and find the intersection points between y=5x and f(x).
First find the length of x using Pythagoras with the lengths 46cm and 24cm.
Then use Pythagoras again to find the diagonal using the lengths x and 20cm.
There should be 2 intersection points. I would need to see your graph to find your mistake.thnaks alot for the help but 1 small doubt for 7,d i made a line on y=5X but there is only one point intersecting with it can u explain a bit plz
First find the length of x using Pythagoras with the lengths 46cm and 24cm.
Then use Pythagoras again to find the diagonal using the lengths x and 20cm.
Which part of 1d?thank you sir i have another question too from the same paper: (q 1d)
Sorry about that. I can see the picture so I don't know why you can't.th
the picture is not shown here
Sorry about that. I can see the picture so I don't know why you can't.
Frequency Density = Frequency / class widthso sorry but it is the second one
Frequency Density = Frequency / class width
So for 60<t<=80:
Frequency density = 14/20 = 0.7
But the height of this column is 2.8cm so they must be using a scale of 1 unit = 4cm.
Now use the formula again to find the frequency density for the other three intervals then use the scale to find the heights of the columns.
Any time you want but please ask only one question at a time.sir i have list of doubts waiting for you,when cn i ask u
Any time you want but please ask only one question at a time.
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