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I'm an IGCSE Maths Teacher - Post your questions here.

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notnek01

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Ijlal Amir said:
could you answer the rest of the question pleaseeeeee Thank you :D
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For similar triangles, the ratio of corresponding sides is equal. You would need to say something like this to get the mark.

Can you solve the equation in the next part? You said that you only lost 1 mark in Paper 2 so I'm guessing that you can do this :)
 
Ijlal Amir

Ijlal Amir

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notnek01 said:
For similar triangles, the ratio of corresponding sides is equal. You would need to say something like this to get the mark.

Can you solve the equation in the next part? You said that you only lost 1 mark in Paper 2 so I'm guessing that you can do this :)
Click to expand...
which one part b ??
 
Ijlal Amir

Ijlal Amir

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ok
notnek01 said:
No part aii, since you asked for help in a).

Can you be very clear about what you need help with: Please say the specific part of the question and all your working/ideas.
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ayight lemme solve aii...... since the ratio of the triangle is
MNO:OPQ WE CAN CONCLUDE THAT
(QO/MO) = (PO/NO)
happy Sir :D
 
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Noorullah Farid

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notnek01 said:
Hello,

It's getting close to exam time and I'm sure there are many past paper questions that students are having difficulty with. I noticed that most questions in other threads go unanswered so I thought I'd make this thread that only contains past paper questions.

So if you have an IGCSE Maths past paper question please give the i) year ii) paper number and iii) question number. Also, you must post all your working/ideas. If you don't tell me where you're up to, I can't (and won't) help you.
Click to expand...

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s08_ms_4.pdf
6c
in this question if we write
y>=0
x<=2
y>=0.5x
y<=2x+4
will it be correct?
the answers are without = but in the question the fifth inequality is given with the = the lines are also bold not broken so what should i do?
 
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notnek01

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mak kings

mak kings

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ON -2008-p4-Q4c. ..y do v take the area of the pentagon also....,,,the prism is only made of 5 pieces of wood ..so v shud take only its surface are...is it...? plz cud u clear my this concept
ON -2008-p4 ..6 a(ii) ..y do v take30.5 as a value as well??
on-07-p4- Q9b-(v) and (vi)
 
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notnek01

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mak kings said:
ON -2008-p4-Q4c. ..y do v take the area of the pentagon also....,,,the prism is only made of 5 pieces of wood ..so v shud take only its surface are...is it...? plz cud u clear my this concept
ON -2008-p4 ..6 a(ii) ..y do v take30.5 as a value as well??
on-07-p4- Q9b-(v) and (vi)
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Q4c. The prism is not made from 5 peices of wood. It is made from a cylinder that has had 5 peices of wood removed. The 5 shaded parts have been removed.

Q6aii. If x=3 you have:

30,30,30,30,30,30,30,30,30,30,31,31,31,31,31,31,31,32,32,32

Then the median is 30.5.


Q9bv. These are powers of 3:

1, 3, 9, 27, ... = 3^0, 3^1, 3^2, 3^3, ...

So the nth term is 3^n.


Q9bvi. Look at sequences S and T: Sequence U is the difference between the terms in S and T e.g. for the first term, 4-1=3 and for the second term, 9-3=6.

Can you work out the nth term?
 
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nemonoorhan

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hey could u please explain for me the whole question of may june 2000 number 5
thanks please as soon as possible
 
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notnek01

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nemonoorhan said:
hey could u please explain for me the whole question of may june 2000 number 5
thanks please as soon as possible
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I'm not going to do the whole question. Which specific parts can't you do?

The syllabus was slightly different back then so I don't think they would ask you a question like 5aii in 2013.
 
usman sharif

usman sharif

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can you please tell me what should I learn for paper 42 math
or can you upload guess paper for paper 42 please :D
 
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Noorullah Farid

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Anas Firoz said:
May june 2003 6B and 6C please
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6bi) 2 1cm length deducted for width, 2 cm length deducted from length, 1 cm length deducted from height( no wood at top) so the dimensions would be
(2x-2) by (x+2) by (x)
6bii) vol of wood = ( ext vol of box - internal vol of box) Note this font means cancelling
=2x(x+4)(x+1) - x(x+2)(2x-2)
=2x(x^2 +5x +4) - x(2x^2 +2x -4)
=2x^3 + 10x^2 +8x -2x^3 - 2x^2 +4x
so 8x^2 +12x

ci) 8x^2 +12x = 1980
8x^2 + 12x- 1980=0
4(2x^2 + 3x -495)=0
so 2x^2+3x-495=0
now use the quadratic formula to solve it would be difficult to show here

cii) after u solve the equation u get 1 positive value and 1 negative use the positive and substitute in place of x for the external dimension
 
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Noorullah Farid

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ZaqZainab said:
http://papers.xtremepapers.com/CIE/Cambridge%20IGCSE/Mathematics%20(0580)/0580_s09_qp_4.pdfQuestion 2 b and c well really easy is it not but i dunno wold you please explain
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2b) it is rolled 50 time (even number) so the 2 numbers would be 50/2 and 50/2 +1 so 25 and 26.. now locate these in the table.. 25th number is 2 and 26th number is 3 so add both and divide by 2 so 2+3=5/2=2.5

c) multiply each frequency by score then add all of them.. then divide by 50 (total number)
 
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