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[ZaqZainab]

2b) it is rolled 50 time (even number) so the 2 numbers would be 50/2 and 50/2 +1 so 25 and 26.. now locate these in the table.. 25th number is 2 and 26th number is 3 so add both and divide by 2 so 2+3=5/2=2.5

c) multiply each frequency by score then add all of them.. then divide by 50 (total number)

Thank you

 

[mak kings]

Q6aii. If x=3 you have:

30,30,30,30,30,30,30,30,30,30,31,31,31,31,31,31,31,32,32,32

Then the median is 30.5.


Y U TUK X =3 ????????? acutally idnt knw at all!

 

[mak kings]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w11_qp_42.pdf Q2 a(ii) ..can u plz lay the detailed working!!!!!

 

[notnek01]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w11_qp_42.pdf Q2 a(ii) ..can u plz lay the detailed working!!!!!

fg(x) = f(g(x)) = f(2/x + 1) = 4(2/x + 1) - 2

= 8/x +4 - 2 = 8/x +2

 

[Majd Aldeen]

hello can u plz tell me for what we may use tracing paper??
in igcse paper4

 

[sweet.sugar]

this is easy but solve this plz
m/j/12 v42 q10,d

 

[notnek01]

hello can u plz tell me for what we may use tracing paper??
in igcse paper4

You can use it for any question if you need it.

It's mainly useful for drawing or describing rotations. It is also useful for some loci questions where you are asked to draw the locus of a point as it moves (this kind of question is pretty rare).

 

[notnek01]

this is easy but solve this plz
m/j/12 v42 q10,d

The LCM of the denominator is 12. So you need to change each fraction so that it has denominator 12:

x / 2 = 6x / 12

5x / 3 = 20x / 12

7x / 4 = 21x / 12


So now we have

6x / 12 + 20x / 12 - 21x / 12

= (6x+20x-21x) / 12 = 5x / 12

 

[inquisitiveness]

hi,in the exam paper(paper 2) I wrote (p+3)(k+m) instead of (k+m)(p+3) as the final answer in the 3rd question... ...is that still correct?

 

[sweet.sugar]

The LCM of the denominator is 12. So you need to change each fraction so that it has denominator 12:

x / 2 = 6x / 12

5x / 3 = 20x / 12

7x / 4 = 21x / 12


So now we have

6x / 12 + 20x / 12 - 21x / 12

= (6x+20x-21x) / 12 = 5x / 12

thanku

 

[inquisitiveness]

(0581)/0581_s11_qp_22
Q.5
in my working,I reached till point where i got 6.04 and 11.422 then I dont know what else to do to continue...

 

[notnek01]

(0581)/0581_s11_qp_22
Q.5
in my working,I reached till point where i got 6.04 and 11.422 then I dont know what else to do to continue...

You've done the hard part, now you just need to say in which currency the meal costs less.

In euros the cost is €6, and in Brunei dollars the cost is €6.04 so the meal costs less in euros.

 

[inquisitiveness]

thank you!!
one more thing,in the finding distance of a line,we have an equation to learn,like if we are given with (5,6) and (6,9)we have an equation to apply to find the distance but what I usually do is I make sort of a triangle kind of thing and i find the line using trigonometry and find the answer which would be the hypotenuse......that method works but is it possible that there is ANY question where my method wouldnt work and i would have to use that formula instead?cause i try my best to learn as less formulas as possible

 

[notnek01]

thank you!!
one more thing,in the finding distance of a line,we have an equation to learn,like if we are given with (5,6) and (6,9)we have an equation to apply to find the distance but what I usually do is I make sort of a triangle kind of thing and i find the line using trigonometry and find the answer which would be the hypotenuse......that method works but is it possible that there is ANY question where my method wouldnt work and i would have to use that formula instead?cause i try my best to learn as less formulas as possible

The distance of a line segment formula is basically Pythagoras' Theorem.

When you use your method, you are using the formula but just not realising that you are!

I also prefer to learn things without formulas. It's easier to see what's going on.

 

[inquisitiveness]

thank you,
when asked about the lower and upper bound,in http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s12_qp_42.pdf q5 c ii,i rounded my answer off to 3 sig. figures because its not specified in the question,so my answers were 51.3 and 52.8 but in the ms it said Lower = 51.3375 final answer
Upper = 52.8275 final answer
...shouldnt i always round my answer to 3 sf?

 

[notnek01]

thank you,
when asked about the lower and upper bound,in http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s12_qp_42.pdf q5 c ii,i rounded my answer off to 3 sig. figures because its not specified in the question,so my answers were 51.3 and 52.8 but in the ms it said Lower = 51.3375 final answer
Upper = 52.8275 final answer
...shouldnt i always round my answer to 3 sf?

CIE has strict rules regarding rounding:

If the answer has less digits than the full calculator display, write down all the digits you see (this kind of number is called 'exact'). If you round your answer, you'll lose marks.

If the answer is not 'exact', round to 3sf and for angles round to 1dp. Sometimes the question will ask you to round to something else so read the question carefully.

Finally, always remember to only round your answer (if it is not exact). If you use rounded answers from previous questions in your working, you will lose marks.

 

[aaaamfa]

need help in the following question:
0580/41/m/j/10
question no. 2b

 

[ZaqZainab]

CIE has strict rules regarding rounding:

If the answer has less digits than the full calculator display, write down all the digits you see (this kind of number is called 'exact'). If you round your answer, you'll lose marks.

If the answer is not 'exact', round to 3sf and for angles round to 1dp. Sometimes the question will ask you to round to something else so read the question carefully.

Finally, always remember to only round your answer (if it is not exact). If you use rounded answers from previous questions in your working, you will lose marks.

i hop you were mt teacher i never knew it

 

[aaaamfa]

another question: in the foolowing paper:
0580/41/m/j/10:
question no.7c1 and 7c3

 

[notnek01]

need help in the following question:
0580/41/m/j/10
question no. 2b

For example, if the mean for 5 students was 22 then the total for these 5 students would be 22*5 = 110. So for n:

The mean for n students is 3 so the total for these n students is 3n.

We also know that the total for the 40 students is 190.

So the total for the (40+n) students is 190+3n. To find the mean, we need to divide this by the number of students (40+n) to get:

Mean = (190+3n)/(40+n)