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Math P1 doubt
- Thread starter arlery
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Its simple man...First find the h by equating it to volume. U'll get 8/x^2=h.
Now simply add all the surface areas and substitute "h". somethin lyk this
A=2x.h + 2(1/2xh) + x^2 and the upper lid i.e 4/5x.54x
and simplify it to get the desired results...
Now simply add all the surface areas and substitute "h". somethin lyk this
A=2x.h + 2(1/2xh) + x^2 and the upper lid i.e 4/5x.54x
and simplify it to get the desired results...
- Messages
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- Points
- 173
Can you solve it in detail ?
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V=Area x height (ryt) where V=4
now area= 1/2.x^2
4=1/2.x^2 x h
therefore h=8/x^2
Now to find surface area:
A= 1/2x^2 + 2(1/2xh) + 2xh + 5/4x.4/5x
simply plug-in the h=8/x^2
1/2x^2 + x(8/x^2) + 2x(8/x^2) + x^2
cleaning it up will give you 3/2x^2 + 24/x H.P(hence proved)
let me know if you got hold of it....
now area= 1/2.x^2
4=1/2.x^2 x h
therefore h=8/x^2
Now to find surface area:
A= 1/2x^2 + 2(1/2xh) + 2xh + 5/4x.4/5x
simply plug-in the h=8/x^2
1/2x^2 + x(8/x^2) + 2x(8/x^2) + x^2
cleaning it up will give you 3/2x^2 + 24/x H.P(hence proved)
let me know if you got hold of it....