math problem(URGENT)

[Ayesha abid]

Can somebody help me out with this Question?

P is the point (2,3) and Q is the point (9,5)

a) find the equation of the line joining PQ.​

b) find the coordinates of the point where the line PQ intersects the x-axis.​

c) the line y=5 is the line of symmetry of triangle PQR. find the coordinates of R.​

d) find the area of triangle PQR.​

e) calculate the length of PQ and hence calculate the perpendicular distance from R to the line PQ.​

 

[PlanetMaster]

a) Since you have points P and Q, their equation would be in the form $y=mx+c$ where
$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$
$m=\frac{5-3}{9-2}=\frac{2}{7}$
Substituting back into $y=mx+c$ and substituting x and y coordinates from either P or Q should give $c=\frac{17}{7}$.

Thus equation of the line joining PQ is $y=\frac{1}{7}(2x+17)$

b) At x-axis, y=0 so $x=-\frac{17}{2}$ and therefore coordinates would be $(-\frac{17}{2},0)$

c) You'll have to either visualize or sketch this. Since line of symmetry is y=5 and Q has coordinated (9,5), R will have same x-coordinates as P and y-coordinates would be 2(5-3)+3 so R will have coordinates (2,7).

d) We can simply use $\frac{1}{2}\times\text{base}\times\text{height}$ where base would be the length PR and height would be length mid-of-PR and Q (refer to your sketch). This would give the area $14 units^{2}$.

e) You can simple use the formula to find length between two points $\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}$

If anything is unclear, feel free to ask and I'll be happy explain in more detail.

 

[Ayesha abid]

thanks

 

[princess of cricket]

Can anybody solve q 27,31,32

 

[Thought blocker]

View attachment 65201

Can anybody solve q 27,31,32

For all of the questions, just bring both sides in the form of a + ib and then equate the real parts with real ones and same for imaginary parts. You will get the solutions by following this method for every questions.