Mathematics P6 NOV 2011

[Emily793]

isnt it 11!/2!x2! ???

 

[anahita16]

Don't know...
Lemme explain my reasoning.
Two EE's together-EE can be considered as one letter only because order doesn't matter here, both letters are E itself.
That leaves me with X T R E M P A P R S EE
E is not same as EE, so I have 11 letters in all, out of which there are 2 P's.
So i got 11!/2! .
Well you see, I missed the fact that there are 2 R's.
So, final answer=11!/2!2!
Yeah you're right. Thanks shressubha and Emily793!!

Anyway i don't really care abt stats now I screwed the paper :fool: I missed the full marks!!!!

 

[AlphaCentauri]

Hmm... why not 11!/ (2!2!2!)?

"Two EE's together-EE can be considered as one letter only because order doesn't matter here, both letters are E itself."

So, there are 2Es, 2Rs and 2 Ps.

 

[Emily793]

you are considering the 2 E's as one whole! thats why you dont include it!

 

[AlphaCentauri]

There are 3 Es. I'm considering only 2 of them as one whole => there are 2Es; one E and one 'EE'.

 

[Emily793]

heys guys how were we supposed to do ques 2?? the head and tail thing??

 

[CaptainDanger]

I completely forgot my answers now.
You don't put them in a recycle bin? It would be much appreciated if you could simply move it back.

If I could... I would have...

 

[anahita16]

heys guys how were we supposed to do ques 2?? the head and tail thing??

I think 2^12...
I listed and calculated all possibilities using 3 coins instead of 12. I got 8. So i figured that would be 2^3=8. Since it was 12 in the question i just substituted 3 by 12 and ended up with 2^12. I'm not sure but it's the best logic I've come up with, like the closest I can get to a sensible answer.

 

[AlphaCentauri]

I completely forgot my answers now.
You don't put them in a recycle bin? It would be much appreciated if you could simply move it back.

If I could... I would have...

No worries.

Anahita, the Pigeon Hole method. It's good. I used the Factorial method, you get the same answer.

 

[anahita16]

 

[AlphaCentauri]

Euhm... = Thank, and = You?

You're ' '

 

[DonOmarCorleone]

how did u get it using the factorial method?

 

[AlphaCentauri]

[12!/11! + 12!/2!10! + 12!/3!9! + 12!/4!8! + 12!/5!7!]*2 +12!/6!6!
Got it right after exams.

 

[1357913579]

but even after that te answer is different to 2^12 right so hows this coorect and why 2 times in the 12!/5!x7!

 

[AlphaCentauri]

Is it different?

 

[1357913579]

se when you do the way you did you get 3301 as the answer whereas if you 2^12 you get 4096 and by the way why do you multiply 2 times to 12!/7!x5!

 

[AlphaCentauri]

You get the same answer. -.-

I multiplied all of these by 2:
12!/11! + 12!/2!10! + 12!/3!9! + 12!/4!8! + 12!/5!7!

There's a bracket there.
And please, it's over. You've other papers.

 

[anahita16]

Euhm... = Thank, and = You?

You're ' '

= welcome here! hehe smiley coding

 

[DonOmarCorleone]

lol so auragirl, u got it wrong ? u just discovered that after the exam XD pretty much the same here

 

[AlphaCentauri]

Yeah, but you missed, I missed it, doesn't mean others missed it too.^

Anyway, stale paper now. Forget it. Prepare for the ones to come.

Thanks Anahita.