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MATHEMATICS PAPER 1 Discussion

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HEy gyuz, hOw was ur paper?

Mine went pretty well..

What was ur ans for the last question? [radius]
 

mau

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well, i lost at least 10 marks. can i still can aggregate 1?
 
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mau said:
well, i lost at least 10 marks. can i still can aggregate 1?

o_O..
yepss im sure u lost them from petty mistakes!!!right!!???like me!!xD
if you work well in p2 u may get a "1" in maths!!! gud luck mate!!! ;) ;) ;)
 

mau

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yes, its all because of these silly mistakes. Can anyone suggest any ways to avoid them because maths p2 and add maths is coming.
 
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That's because in p1 we are not allow to use calculator !

But I fink if give ur best in p2, u'll get a distinction definitely !

Work as many exam papers as u can ! about 12 papers!
 
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bamteck said:
HEy gyuz, hOw was ur paper?

Mine went pretty well..

What was ur ans for the last question? [radius]
mine radius was 7.5cm


what about u ????????? :)
and what about the question which asked the special name for SQUARE OF 89 ????????
 
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usama1993 said:
bamteck said:
HEy gyuz, hOw was ur paper?

Mine went pretty well..

What was ur ans for the last question? [radius]
mine radius was 7.5cm


what about u ????????? :)
and what about the question which asked the special name for SQUARE OF 89 ????????

its irrational number!!!:p :mrgreen: :mrgreen: :mrgreen:
 
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yepx.. its irrational number.. xD

As f0 the questi0n 0n Radius.. i g0t 8.5cm :S
 
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I got 8.5 cm as well for the radius.

@usama Did you do the same paper as us? Because i remember the question being "What is the special name for the Square root of 61?"
 

XPFMember

XPRS Moderator
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yeah its possible like that...u both surely wud have done different varients!! :)
 
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hey guys,
what is the answer for the speed-time graph??First part i got 30 S..
and also for the triangle there you are asked to find AC and cos DAC???
For AC i got 12.5cm and for cosDAC i got -7/25...

is it good?????
 
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Yeah i got the same answers as you for both questions.

For the last part of the speed time graph question, i think i got 110 s.

And you?
 
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@ Heshna ;; It was a parallelogram !

Yea that's the Answer! :)

The aggregate "1" means a disntinction [A]
 
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You find the length of one arc = (8O/360) x 2 x pi x r
= (4/3) r

Multiply by 3 to obtain the total length of the 3 arcs = 4r

There are 6 radii in total so you add them up to the arcs to find the total length of wire.

6r + 4r = 85 cm

10r = 85

r= (85/10)
= 8.5 cm
 
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total length of wire given was 60cm. my radius was 7.5cm.. and i used 40/360 instead of 80 , because it was the circumference of the 40 degree sector.
 
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