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Mathematics Paper 42, Doubts, Hard Questions

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Mr.Physics

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MY NAME HERE U GO
Q 11 (b)
first find the area of sector
area of sector = 22/360 x 3.142 x (12)^2 = 27.6496 cm ^2
now arc length = 22/360 x 2 x 3.142 x 12 = 4.608 cm

now area of curved part = arc lenght x height = 4.608 x 7 = 32.256 cm^2
now shaded area will be 27.6496 + 32.256 = 59.91 cm^2

HOPE IT HELPED !!!!!!
 
Mr.Physics

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Q 3 (b)

as u know that 100 cm = 1 m
then 1 cm = 1/100 m
take cube on both sides
(1 cm) ^3 = (1/100 m )^3
1 cm ^3 = 1/1000000 m ^3
now u have the volume of cone = 314.2 cm^3
multilpy 314.2 on both sides
314.2 cm ^3 = 1/1000000 x 314.2

the answer is 3.142 x 10^-4 m^3

HOPE THIS ALSO HELPED !!!!!!!
 
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Mr.Physics said:
Q 3 (b)

as u know that 100 cm = 1 m
then 1 cm = 1/100 m
take cube on both sides
(1 cm) ^3 = (1/100 m )^3
1 cm ^3 = 1/1000000 m ^3
now u have the volume of cone = 314.2 cm^3
multilpy 314.2 on both sides
314.2 cm ^3 = 1/1000000 x 314.2

the answer is 3.142 x 10^-4 m^3

HOPE THIS ALSO HELPED !!!!!!!
Click to expand...
hey u got the wrong question!
 
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