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Okay so First you need to know what OB is it is 3p+3w okay!Hi. Can anyone help me with this question (highlighted in the question below)? I think I've forgotten how to solve this and can't seem to find the method anywhere in my notebook. Please help? Thanks in advance.View attachment 23126
Okay so First you need to know what OB is it is 3p+3w okay!
Then you need to understand wht |p| and |w| means Well it basically is root of p2 and root of w square! The Root of p^2=5 and root of w^2=5
The root and square crosses out! so that means P=5 AND W=5
Now you write down ob in |ob| form so it is |OB|= Root of (3p)^2+(3w)^2
Now you have |OB|=Root of (3*5)^2+(3*5)^2
|OB|=Root of (15)^2+(15)^2
|OB|=Root of 450
I have got 21.2 as the answer! i hope it is right i tried my best and if you need help with anything else ask so
Wow. I don't think I've been taught this. Thank you so much! I understood what you've explained and yes, its correct (I checked the mark scheme) but I have a couple of questions.
Thanks once again!
- Does |x| or |y| always mean 'root of x square' or 'root of y square'?
- In the 4th step, can you explain why do we it as 'root of (3*5)^2 + (3*5)^2' and NOT as 'root of (3*5 + 3*5)^2' ? I'm sorry if my question is bothersome or anything but the thing with Math is if I don't understand the concept, I tend to forget. If you can't answer it, its fine as long as you tell me that is this the method I'l always use in such types of questions?
Here you just use your Calculatorplease can any one explain me the question 18 part d of paper 4024/11/o/n/11
Need help with any question ask i will explain!how can i solve paper 4??
well i have alot of doubts!Need help with any question ask i will explain!
No problem i will help you with as much as i canwell i have alot of doubts!
no i am in UAEno i dont have them.. thankuuu so muchh!!! r u i Jeddah???
You are welcomeno i dont have them.. thankuuu so muchh!!! r u in Jeddah???
Thank you so very much! I understood the concept completely. And as to why we use the Pythagoras Theorem, I got that too. Basically, if we have column vector b = ( 2 3 ) [i 'm sorry I can't write it in a matrix form here] that would mean two units to the right of the x axis , and 3 units upwards of the y axis. That would create a triangle and the hypotenuse would represent the magnitude of b. And since we use the Pythagoras Theorem to find the length of the hypotenuse in a right angled triangle, we use the same method to find the magnitude of b here. Right?1. YES It is know as the modulus of a vector which represents the Length of magnitude the vector!
2. Well i am not sure about this one but As my text book which is "Mathematics for IGCSE Extended by David Rayner" says it is represented like root of x^2+y^2
because it uses the pythagoras Theorem! Which you may Know if not "http://en.wikipedia.org/wiki/Pythagorean_theorem" Lets take an example a^2 =b^2+c^2
so this is a pythagoras! now we take the Square of "a" to other side so as you see it would be a=root of b^2+c^2 and not a=root of (b+c)^2 Now you would ask me why do we use the pythagoras theorem it isn't mentioned in my book and not needed to know for our syllabus! i hope this helped! And if you need any more help do ask me
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s12_qp_42.pdf ques 8b/c please! really bad in probabilities
it tells u that "The formula for the total number of one centimetre lines needed to draw all of the first n
I don'tget the concept of adding 3+ for the diagram 2 why is that we have to add the previous diagrams liens?it tells u that "The formula for the total number of one centimetre lines needed to draw all of the first n
diagrams is an^3+bn^2+n" so for each diagram u will add to it the number of one centimeter lines of the previous diagram so for example in diagram 2 u will add ur total number of one centimeter lines to diagram 1 lines so it will be a(2)^3+b(2)^2+2=9+3...... Hope U understood it
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