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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!
SEE
The cost of each book is increased by $2 so the total number of books bought now can be 40/x+2
The books that can be bought now are one less then the (part i) so they are 40/x - 1
As both of them show number of books you can equal them 40/x - 1 = 40/x+2 and then solve...
MATH ANGEL
You don't mind us answering? Right?
Pernee26 said:Question 8 a) ii) please solve it.
http://www.xtremepapers.me/CIE/Cambridge IGCSE/0580 - Mathematics/0580_w05_qp_4.pdf
SEE
The cost of each book is increased by $2 so the total number of books bought now can be 40/x+2
The books that can be bought now are one less then the (part i) so they are 40/x - 1
As both of them show number of books you can equal them 40/x - 1 = 40/x+2 and then solve...
MATH ANGEL
You don't mind us answering? Right?