nothe mark scheme says 154 for ACE.. Please check it, ON 2009,P22
AND also BCE and DBC can be co interior angles right? that means theey should be supplementart?? how can it be equal to 68 then? :S
/_ DBO and /_ COB are supplementary
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nothe mark scheme says 154 for ACE.. Please check it, ON 2009,P22
AND also BCE and DBC can be co interior angles right? that means theey should be supplementart?? how can it be equal to 68 then? :S
any line extending from the circumference of a circle towards the centre is equal to any other line extending from the circumference of a circle towards the centrealso bro how is triangle OCA an isosceles triangle how can u find it and tell?
thanks bro! so according to that. even that should apply in this question as well?any line extending from the circumference of a circle towards the centre is equal to any other line extending from the circumference of a circle towards the centre
thus OC = OA
no there are 2 methodsguys the question number 7. will angle 37 be equal to angle c? as the rule applies co interior angles are supplementart or do they add up to 180? :S
PLEASE HELP GUYS!View attachment 37334
Bro. How? I mean see, 90-37= 53,no there are 2 methods
(1) c + 90 + 37 = 180
c = 53
(2) 90 - c = 37
c = 53
Yes you are right , that is another way of solving itBro. How? I mean see, 90-37= 53,
its an isoceles, so if thts 53, eve the 2nd angle c is 53
am i right?
easy, just say since 4 terms = 30 and 3 terms = 14, then you can form a simultaneous equation.PLEASE HELP ME WITH THIS!
see bro lsn! the question i gave u now is quite similar to this circle theorEm.
see im really confused, not aasking you to solve the whole question,
BUT angle p and angle r SHOULDNT THEY BE CYCLIC QUADRILATERAL AND ADD UP TO 180"? darn! and the same thing in previous quest
1st ans :
96
48
97 how
35 how
Thanks so mucheasy, just say since 4 terms = 30 and 3 terms = 14, then you can form a simultaneous equation.
[a(4)^3+b(4)^2+4/6]=30
[a(3)^3+b(3)^2+3/6]=14
64a+16b+4/6=30
27a+9b+3/6=14
64a+16b=30-4/6
27a+9b=14-3/6
64a+16b=29.3
27a+9b=13.5
now all you have to do is solve the simultaneous equation to find the values of a and b
thanks!easy, all you have to do is use the circle properties
(iii) to find angle SPQ you have to do the following:
<QRP=<QSP=35 and <PRS=<PQS=48
therefore,
<SPQ= 180 - (<PQS + < QSP)
= 180 - ( 48 + 35)
= 180 - 83
= 97
(iv) use <QRP=<QSP=35
Q9Help in the 1st quest please..
Q9
b)
i) it is written 'Union' of the 2 sets, not intersection. so the answer will be 8.
ii) P' intersection Q' = {elements of epsilon except the elements of P} intersection {elements of epsilon except that of Q)
= {1, 2, 3, 4, 5} int. {4, 5, 6, 7, 8)
= {4, 5}
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