Mathematics: Post your doubts here!

[The Chill Master]

use (theta/360 * 2pir) *3 + (the three straight lines aligning the peri...)

i want c i answer how to find 120 degrees

 

[Mavilda Bucket]

View attachment 41863

got itttttttttt
jzk loadssssssssssssss

 

[Ameena Eesa]

got itttttttttt
jzk loadssssssssssssss

Nvm

 

[The Chill Master]

Nvm

please i need c i answer

 

[Ameena Eesa]

please i need c i answer

Can't get it... it's something about tangents and the quadrilateral equalling 360...

 

[princess sofia]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_43.pdf
Q6(c)
one is going to b 0 , wt abt others?

 

[The Chill Master]

need q10 last part answer
Awesome12
shoaib672002
Ameena Eesa
***amd***

 

[princess sofia]

Help nedded
Awesome12
ahmadumar
Mai(M4!)
Thought blocker
shoaib672002
***amd***
Emadthegreat

View attachment 41805 View attachment 41806 View attachment 41807

 

[Mavilda Bucket]

shw d b part plsss

i got 4,29,46

bt d ms says 4,30,53

 

[My Name]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w11_qp_42.pdf

question 1 part d
question 3 part a iii
question 6 part c
question 7 part b,f i and ii GRAPH I SSOOO weird
question 9 part a ii and b

 

[Layla..]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_41.pdf
Can anyone help me answer Q 10 a part V? Thanks

 

[The Chill Master]

thanx a lot sis

 

[The Chill Master]

thanx a lot

 

[Layla..]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w11_qp_42.pdf

question 1 part d
question 3 part a iii
question 6 part c
question 7 part b,f i and ii GRAPH I SSOOO weird
question 9 part a ii and b

1 part d) 540(1+6%)^2 = 606.744
They say it was put 2 years ago means compound interest for 2 years has been given thus the formula
Q3 part aiii) Use englargement matrix and multiply it with the coordinates or make x and y lines at (4,5) and mark coordinates of the triangle along this line then simply mutiply coordinates by 1.5

 

[Layla..]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w11_qp_42.pdf

question 1 part d
question 3 part a iii
question 6 part c
question 7 part b,f i and ii GRAPH I SSOOO weird
question 9 part a ii and b

Q 6 part c) TSA = curved surface area of the frustum i.e area of the larger cone - area of the smaller cone + pie x 1.5^2 ( area of the base of smaller cone) +pie x 3^2 + 2 x pie x 3 x 12

 

[Layla..]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w11_qp_42.pdf

question 1 part d
question 3 part a iii
question 6 part c
question 7 part b,f i and ii GRAPH I SSOOO weird
question 9 part a ii and b

The graph can be weird llol, for part f
x(x^2 - x -2) = -1
x^2 -x-2 =-1/x
-1/x = x^2 - x - 2
-1/x - x^2 = -x-2
1/x + x^2 = x+ 2

fii) Draw the graph for y= x + 2

 

[My Name]

Awesome12
ahmadumar
Mai(M4!)
DeadlYxDemon
Evangeline
a_wiserME!!
any other person whocan help ur MOST WELCOME!
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_42.pdf
question 1 part c
question 3 part b
question 4 part b and d
question 5 part b ii
question6 part b ii steps

question7 part b iii
question 10 part v

PLEASE AND THANKU!

 

[Layla..]

ahmadumar
Mai(M4!)
DeadlYxDemon
Evangeline
a_wiserME!!
any other person whocan help ur MOST WELCOME!
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_42.pdf
question 1 part c
question 3 part b
question 4 part b and d
question 5 part b ii
question6 part b ii steps

question7 part b iii
question 10 part v

PLEASE AND THANKU!

Done with this paper just wait a sec

 

[My Name]

I AM SO SORRY
AN SO FREAKING OUT I POSTED THE WROND LINK !!!!
HOPE U WILLSTILL HELP
ME
ANS CONQUDINK i needed those answers tooo!!!!!!!!!!!!!!!!!!!

 

[My Name]

there is no part c for 1
3)b)volume=width*length*hieght=(9-2x)(7-2x)(x)
x(9*7+9*-2x+-2x*7+-2x*-2x)
63x-18x^2-14x^2+4x^3
=4x^3-32x^2+63x


4)b)pentagon=5 sides
n=5
180(n-2)=sum of interior angles
180*3=540


d)i)sum of interior angles of quadrilateral =360
4x-5+3y-20+2x+5+x+y-10=360
rearrange it to be 4x+2x+x+3y+y=360+5+20-5-+10
=7x+4y=390

(ii)as AD and BC are parallel then 2x+5+3y-20=180
rearrange it to be 2x+3y=180-5+20
2x+3y=195

(iii)2x+3y=195
7x+4y=390
you can use a lot of ways to answer a simultaneous equation but i enjoy the substitution the most
so here is it
y=(195-2x)/3
y=(390-7x)/4
(195-2x)/3=(390-7x)/4
65-2x/3=97.5-7x/4
7x/4-2x/3=97.5-65
x=32.5/(13/12)=(12*32.5)/13=30
y=(195-2*30)/3=45

(iv)use the answer in iii
it should be
65
65
115
115


5)b)ii)both uses the internet=3/5*3/4=9/20
Chaminda uses it=3/5*1/4=3/20
Niluka uses it=3/4*2/5=3/10
9/20+3/20+3/10=9/10


Q 6 no ii is found so i answered b
6)b)Surface area =circumference of biggest semi-circle*height+circumference of smallest semi-circle*height+circumference of semi-circle with diameter 17.5*height +area of cross section (solved in a )
1/2π (17.5+6.5)*35+1/2π(6.5)*35+1/2π (17.5)*35 +329.7=1/2π (17.5+6.5+24)*35+329.7=420π +306.25π +113.75π +329.7=840π +329.7=2968.6 but as it should be 3 s.f. so it is equal 2970



7)b)iii)x=8--4=8+4=12
y=14--4=14+4=18


no 10 v

U MADE IT SEEM SOO EZ how long did it take u to do this!