post a qustion ill try to do iti've got no time at all !!! only if someone could explain plz !!! :}
and u plz solve my questions
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post a qustion ill try to do iti've got no time at all !!! only if someone could explain plz !!! :}
i'll try {FYI i'm not so gr8 at maths!!!} :]post a qustion ill try to do it
and u plz solve my questions
xcus eme is this te one i asked forPart b Solution
360 x 2/3 = n^2 +3n +2
240= n^2 + 3n +2
so
n^2 + 3n + 2 = 240
n^2 + 3n + 2 -240= 0
n^2 +3n -238 = 0
n^2 +17n -14n - 238 =0
n(n +17)-14(n+17) = 0
(n+17)(n-14)=0
Since n cant be negative so n-14= 0 so n is 14
same herei'll try {FYI i'm not so gr8 at maths!!!} :]
oh thnxJust solve normally..... the fg(x)
(2x+7)^2 + 2x+7 - 3
2x(2x+7) +7(2x+7) +2x+7 - 3
4x^2 + 14x + 14x + 49+ 2x + 4
4x^2 + 30x + 53
compare this with the original equation
4x^2 + 30x + 53 = px^2 + qx + r
in place of p = 4
in place of q= 30
in place of r= 53
correct to 1 dp means the error cud be 0.5 ie( 1 divided by 2)View attachment 41899part e please
for eg a question says a tyre has a daiameter of 12cm to the nearest cm. calculate upper and lower bound?i've got no time at all !!! only if someone could explain plz !!! :}
correct to 1 dp means the error cud be 0.5 ie( 1 divided by 2)
it can be plus or minus 0.5
so
for lower u minus 0.5 and for upper add 0.5
use the formula fr peri and find out
if u dont get this tell me !
the thing that i don't get is why do we divide it by 2???for eg a question says a tyre has a daiameter of 12cm to the nearest cm. calculate upper and lower bound?
the 1st thing u do is divide the unit u have by 2
(1/2)=0.5
upper bound =12+0.5=12.5
lower bound=12-0.5=11.5
explain me d triagle ka nais your answer 6.614? and is x= 2.5?
Yes? You said Q 9 of P43 O/N 2013... :/xcus eme is this te one i asked for
it's a rule.the thing that i don't get is why do we divide it by 2???
First one is easy! substiture 1 in the formula and the formula = 9 as the n is 1GUYS NEED HELLPPP........
I'm stuck on this question, from O580/43/O/N/13 (October November 2013, 43, IGCSE)
It's Question 9ci and 9cii
c) The total number of lines in the first n diagram is 1/2n^3 + pn^2 + qn
i) When n=1, show that p+q=8.5
ii) By choosing another value of n and using the equation in part (c)(i), find the values of p and q.
Need help ASAP.
Link to the paper: http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w13_qp_43.pdf
umm.. i checked the marking scheme and your answer is wrong i also did the working it's supposed to be:-perimeter of rectangle=2L+2W
2(23.7)+2(10.9)=69.2
hence it is correct t 1 d.p (1/2)=0.5
L.b=69.2-0.5=68.7
U.b=69.2+0.5=69.7
For every upper bound and lower bound question??it's a rule.
SOORRRY i found the perimeter then did the U.b and L.b.umm.. i checked the marking scheme and your answer is wrong i also did the working it's supposed to be:-
U.B 23.7+0.5 =23.75 10.9+0.5=10.95
23.75+23.75+10.95+10.95=69.4m
L.B 23.7-0.5=23.65 10.9+0.5+10.85
23.65+23.65+10.85+10.85=69m
First one is easy! substiture 1 in the formula and the formula = 9 as the n is 1
for second one use simultaneous equation
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