Mathematics: Post your doubts here!

[Danish Sardar]

Anybody can plz upload a maths formula sheet for igcse it would be great
Thanks in advance

 

[Mr.Physics]

Question: 25% of a magazine is used to sell 2nd hand cars . 62.5% of the remaining pages were used to show other things and 36 pages of them were used for advertisement ..HOW MANY PAGES ARE THERE TOTALLY??????? TIP : ONLY 17% IN THIS WHOLE WORLD GAVE THE ANSWER WRITE AS MY TEACHER SAID .IF U WANT TO BE THE 18 TH % TTTRRRRYYYYY THHHIISSSSS

Btw don't you think you have exagerrated this one like only 17% of the world solved this LoL !!
Solution:

Let the total pages= y
Percentage of pages used for selling cars= 25% of y = 0.25y
Remaining percentage= 100 - 25 = 75%
The percentage of remaining pages = 75% of y = 0.75y
62.5% of remaining pages = 0.75y x (62.5/100) = 0.46875y (Do not round this off if you want an accurate answer)
Pages for ads= 36

Therefore the equation becomes like this

0.25y + 0.46875y + 36 = y
0.71875y + 36 = y
Y - 0.71875y = 36
0.28125y=36
Y= (36/0.28125) = 128

Cheers ! I hope you'd get it !

 

[Danish Sardar]

Btw don't you think you have exagerrated this one like only 17% of the world solved this LoL !!
Solution:

Let the total pages= y
Percentage of pages used for selling cars= 25% of y = 0.25y
Remaining percentage= 100 - 25 = 75%
The percentage of remaining pages = 75% of y = 0.75y
62.5% of remaining pages = 0.75y x (62.5/100) = 0.46875y (Do not round this off if you want an accurate answer)
Pages for ads= 36

Therefore the equation becomes like this

0.25y + 0.46875y + 36 = y
0.71875y + 36 = y
Y - 0.71875y = 36
0.28125y=36
Y= (36/0.28125) = 128

Cheers ! I hope you'd get it !

Yeah man nice one

 

[Danish Sardar]

Btw don't you think you have exagerrated this one like only 17% of the world solved this LoL !!
Solution:

Let the total pages= y
Percentage of pages used for selling cars= 25% of y = 0.25y
Remaining percentage= 100 - 25 = 75%
The percentage of remaining pages = 75% of y = 0.75y
62.5% of remaining pages = 0.75y x (62.5/100) = 0.46875y (Do not round this off if you want an accurate answer)
Pages for ads= 36

Therefore the equation becomes like this

0.25y + 0.46875y + 36 = y
0.71875y + 36 = y
Y - 0.71875y = 36
0.28125y=36
Y= (36/0.28125) = 128

Cheers ! I hope you'd get it !

How did u get that 0.28125

 

[Mr.Physics]

How did u get that 0.28125

See there mate.
1y - 0.71875y=0.28125y

 

[husnain99]

How to calculate the answer of C -part 2 .?
Ans is 1 & 10 !

 

[Mr.Physics]

View attachment 58102
How to calculate the answer of C -part 2 .?
Ans is 1 & 10 !

husnain99

 

[husnain99]

husnain99

Thanks !
Btw how many past papers did you do for igcse phy , Chem , bio and maths ? ( from which year till which which year ?)

 

[Mr.Physics]

Thanks !
Btw how many past papers did you do for igcse phy , Chem , bio and maths ? ( from which year till which which year ?)

To be honest, I loved solving math papers. That'swhy I started from 1990s. Sounds crazy
For other subj that you have mentioned, I started from 2004 or 2005

 

[Mr.Physics]

Thanks !
Btw how many past papers did you do for igcse phy , Chem , bio and maths ? ( from which year till which which year ?)

No prob

 

[husnain99]

To be honest, I loved solving math papers. That'swhy I started from 1990s. Sounds crazy
For other subj that you have mentioned, I started from 2004 or 2005

All variants ?
Wow

 

[Mr.Physics]

All variants ?
Wow

Yeah mostly

 

[My Name]

question 2 part c ii of
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s03_qp_4.pdf
Explanation needed.Please and thank you!

 

[husnain99]

question 2 part c ii of
http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s03_qp_4.pdf
Explanation needed.Please and thank you!

360 -(x-45)
x was 130 so ;
=360 -( 130-45)
=360-85
=275

 

[My Name]

360 -(x-45)
x was 130 so ;
=360 -( 130-45)
=360-85
=275

sorry I meant part i

 

[husnain99]

sorry I meant part i

225 ?
You were done with IGs , no ?

 

[Mr.Physics]

sorry I meant part i

The bearing of D from A is 090 so that angle in between is 45. Extend the line from C and that angle will be 45 too.
Bearing of A from C = 180 + 45 = 225°

 

[Mr.Physics]

225 ?
You were done with IGs , no ?

Maybe she wants to repeat Math in the upcoming session

 

[My Name]

225 ?
You were done with IGs , no ?

Yep that one.
Yes,I'm done with it.

The bearing of D from A is 090 so that angle in between is 45. Extend the line from C and that angle will be 45 too.
Bearing of A from C = 180 + 45 = 225°

Thanks!

Maybe she wants to repeat Math in the upcoming session

Haha no Alhamdulillah I'm not repeating anything.
Someone asked me to help out with this. Sadly I couldn't so that's why I'm here.

Thanks both!
Help is appreciated.

 

[Mr.Physics]

Yep that one.
Yes,I'm done with it.

Thanks!

Haha no Alhamdulillah I'm not repeating anything.
Someone asked me to help out with this. Sadly I couldn't so that's why I'm here.

Thanks both!
Help is appreciated.

Oh ok nevermind
My guesses mostly prove incorrect