Mathematics: Post your doubts here!

[Anum96]

My apologies for posting in the wrong thread! and yeah..I'm in A'Level sooo I'v to do it? was so excited to skip you know that excitement when you can't understand something and you check the syllabus with the hope that it isn't included

If it's in your syllabus then yes
& Hahaha! I can relate

 

[Salman Dhillon]

IGCSE Mathematics Topical Past Papers needed ?
Thanks in Advance

 

[Danish Sardar]

But the answer in the textbook is a bit differrnt can u check its exercise 9 ans 19 Mr.Physics

 

[Mr.Physics]

But the answer in the textbook is a bit differrnt can u check its exercise 9 ans 19 Mr.Physics

Yar wo -1 ko common lo phir ye ans aa jaye ga

 

[acecie]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s15_qp_43.pdf

pls explain qs 6(a) and 8(d)

TIA

 

[fleurisabelle]

Question 13 or 14 somebody?

 

[Mr.Physics]

Question 13 or 14 somebody?View attachment 58757

Are these questions for AS ?

 

[fleurisabelle]

Are these questions for AS ?

I think they are covered in A2 I'm not sure though

 

[Mr.Physics]

I think they are covered in A2 I'm not sure though

These are surely for A2 then :/

 

[fleurisabelle]

These are surely for A2 then :/

you are taking AS?

 

[Mr.Physics]

you are taking AS?

Yep

 

[fleurisabelle]

http://papers.xtremepapers.com/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s15_qp_43.pdf

pls explain qs 6(a) and 8(d)

TIA

Q6: (a) Draw a line through AD
∠EDA=70
∠FAD=∠EDA (corresponding angles)
since we have a quadrilateral now (EFAD)
so applying the fact that sum of interior angles of a quadrilateral =360:
∠EFA+∠FED+∠EDA+∠FAD=360
∠EFA=360-70-70-120
=100

 

[delta.charlie321]

How do we know if we draw a line through AD it bisects the angle EDC as mentioned in the above answer post? According to Examiner report the assumption angle EDA = angle FAD = 70° is wrong. Please help.

 

[fleurisabelle]

Since ED is parallel to AB and FA is parallel to DC, angle EDA equals BAD...just imagine like you rotate EDC upside down, image:
compare it with the FAB line, aren't they the same?, the double-arrowed parallel line running in the same way as the single-arrowed ones... this I did just to give you an idea why the angle EDA equals BAD and as the mark scheme says EDA does not FAD, it is true: FAD equals DAB not EBA....hope I explained

 

[delta.charlie321]

Since ED is parallel to AB and FA is parallel to DC, angle EDA equals BAD...just imagine like you rotate EDC upside down, image:View attachment 58912
compare it with the FAB line, aren't they the same?, the double-arrowed parallel line running in the same way as the single-arrowed ones... this I did just to give you an idea why the angle EDA equals BAD and as the mark scheme says EDA does not FAD, it is true: FAD equals DAB not EBA....hope I explained

So how do you find angle EDA? You cant just assume drawing a line from A to D will halve the the angle EDC (140).

 

[fleurisabelle]

So how do you find angle EDA? You cant just assume drawing a line from A to D will halve the the angle EDC (140).

you are right...that doesn't make it half! I'm thinking...maybe I did wrong

 

[Anum96]

How do we know if we draw a line through AD it bisects the angle EDC as mentioned in the above answer post? According to Examiner report the assumption angle EDA = angle FAD = 70° is wrong. Please help.

What's your question? You need EFA?

 

[Anum96]

Question 13 or 14 somebody?View attachment 58757

question 13 is solved in Alevels thread. Rizwan solved it. I'll tag you there.

 

[delta.charlie321]

What's your question? You need EFA?

My question is how do you calculate EFA?

 

[fleurisabelle]

question 13 is solved in Alevels thread. Rizwan solved it. I'll tag you there.

I found it already...thank you missy!