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Mathematics: Post your doubts here!

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by pressng 5 tym m gettng a clear disply nothng else....
MODE button... u should get
1st screen : COMP CMPLX
2nd screen : SD REG BASE
3rd screen : EQN
4th screen : Deg Rad Gra
5th screen : Fix Sci Norm
u need to choose Sci
(i have a fx-100MS but i thinkits da same 4 ur version... Casio try?)
 
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MODE button... u should get
1st screen : COMP CMPLX
2nd screen : SD REG BASE
3rd screen : EQN
4th screen : Deg Rad Gra
5th screen : Fix Sci Norm
u need to choose Sci
(i have a fx-100MS but i thinkits da same 4 ur version... Casio try?)
ohh yeah now i get but my func r lil bit diffrnt may be bcz of fx-82 anyhow i gt the way thankyou shoo muchh.....
 
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In triangle ABC, Angle A is a right angle and D is a point on AC such that BD bisects angle B. If B^DC= 100 calculate ^C ( angle C
 
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In triangle ABC, Angle A is a right angle and D is a point on AC such that BD bisects angle B. If B^DC= 100 calculate ^C ( angle C

ADB + 100 = 180 (angles on a straight line bla bla bla)
ADB = 80 degrees

ADB + angle A + angle B/2 = 180 (angles in a triangle add up to 180)
80 + 90 + B/2 = 180
B/2 = 180 - 170
B/2 = 10
B = 20

A + B + C = 180 (angles in a triangle add up to 180)
90 + 20 + C = 180
C = 70 degrees
 
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In triangle ABC, Angle A is a right angle and D is a point on AC such that BD bisects angle B. If B^DC= 100 calculate ^C ( angle C
<BDA = 180 - 100 = 80 (angles on a straight line)
we already know <DAB = 90 hence we can find <DBA = 180-(90+80) = 10
<CAB = 20 (as it is double of <DBA)

now use the fact that angles of a triangle = 180....
<ACB = 180 - (90 + 20) = 70
 

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Messages
2,951
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17,783
Points
523
ADB + 100 = 180 (angles on a straight line bla bla bla)
ADB = 80 degrees

ADB + angle A + angle B/2 = 180 (angles in a triangle add up to 180)
80 + 90 + B/2 = 180
B/2 = 180 - 170
B/2 = 10
B = 20

A + B + C = 180 (angles in a triangle add up to 180)
90 + 20 + C = 180
C = 70 degrees
LOLzzziess! we answered at da same tym i guess :p
 
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