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Mathematics: Post your doubts here!

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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

Cool! Thanks Math_angel!
 

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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

no problem..my pleasure!!
 

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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

so result's after two months....hope u all get good grades...Aameen!!
 
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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

I'm giving GCE O level maths in june 2011
 

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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

I'll be glad to help u if u need any!! :)
 
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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

thank you math_angel

hope you get straight A* IN YOUR AS subjects inshallah ameen
 

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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

Aameen... Thanks for ur prayers!!
 
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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

I am having a lot of problems regarding vectors and sequences . Any help will be highly appreciated =)
Thanks =)
 

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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

for sequences u see one of my previous posts...for vectors let me know what difficulty do u have ?? :)
 

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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

Math_angel said:
Assalamoalikum!!
Look ....Sequence seems to be hard but actually if u use a little bit of ur brain :p u will surely find it easy!!Believe me!!Just look at the question ....the first few parts are easy and the next part which u will find hard ...will be based on these easy parts that is a combination of those answers or there will be some relation which varies according to the question!!
Eg.if u r given a table with first four columns like n=1 ....to ....n=4 and then u wil have a column for n
this table will have info abt three sequences and u will have to find the nth term!!now the first two will be simple one ...like some addition or multiplication which u can do by the rules or formulas u have...however for finding the third one u will have a problem...but if u look carefully u will find that there may be some relation with the first two sequences...may be multiplying the first two gives the third one or adding them may give the third one ...so what ever it is u will find nth term in the same way like suppose the first two are multiplied togethr to give the third one so to find the nth term for the third one u multiply the nth terms of the first two!!That simple.... :)
So this was smthng complicated ...other type is usually nt that hard!!If stuck at any question...i'll be glad to help...so plz don't hesitate!!
Hope this helps !!
Jazak ALlah Khair!!
 
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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

i know this is out of the relevancy of the topic but can you help me with mathematics extended may/june 2003 qp-1
questions 5, 11, and 13 please?? :?
 

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Re: IGCSE Maths Tips nov.2010!Confused!have questions?Post h

oh sorry ...i forgot to change the topics name....actually i had changed due to the exams but this section is basically fo r all help in maths!! :)

i'll see to ur question soon....and clear it :)
 

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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

I'm so sorry for the late reply ..... i totally forgot to check it!! So it's better if u post the link of the paper as well with ur doubts so i can check it then and there!! :)

btw u have said mathematics extended but the questions u said is from paper 1 which is for core...ofcourse u can do these questions for practice but i'm just saying to make sure that u have doubt in paper 1 only and u havent said it by mistake :)
Anyways for ur questions :

Q:5 all what u have to do is find 42% of 550 000 and add this value to 550 000 since the question says that it increases by 42% of 550 000
or another method..if u can understand...afterincrease it'll be 142% of 550 000 so simply find whats 142% of it!

Q:11 solving the simultaneous eqns. add both the equations the b terms will get cancel so u'll have the eqn as

3a + a = 7 + 5

4a = 12

a = 3


Q:13 (a) total time = 35 + 40 = 75 minutes = 1 h 15 min

so if it starts at 18 50 add 1 15 to it u'll get 20 05...if u have problem in this calculation let me know :)

(b) now remember one point for avg. speed never add two speeds togetherand take the average...always what u have to do is find the total time and total dist. and then using the formula dist./time find the avg. speed...i know here might be there's no chance doing that mistake but just speaking in general bcoz i know this is a common mistake :)

(i) anyways total time is 75 minutes and total dist. is 10 + 20 = 30 km

so avg speed = dist./time = 30km/75min = 0.4 km/min

(ii) 1 min = 1/3600 h

so 0.4km/1min = 0.4km/(1/3600)h = 1440 km/ h



I hope u understood....any doubts let me know :)
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

thanks so much
you made my day :D jazak allah 5air
 

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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

no problem ...any time :)
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

:(
I Know this might sound silly..
But Right know in our schools we are having a 2-weeks Christmas break,, After it directly, we have Pre-Mock examinations..
I have maths first day, I cant seem to be in contact with my teacher,,,
I need to know how to find F-1 (x )
the F inverse x !!!
..
Kindly..
 
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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

OrlandoBloom<3 said:
I am having a huggeee problem with graphs !
Especially ones involving curves !
I cannot figure out what we are supposed to know for the exam !
Please help !
Jazakallah =)
Plus this question is giving me a headache :p
http://www.xtremepapers.net/CIE/Cambrid ... _qp_43.pdf
Question 6 part C & D

Oh my, Is that me or everybody..
I hate Graphs :(
 

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Re: Maths made easy =) stuck sumwhere?Ask ur doubts here!!

Assalamoalaikum!!



Rahma Magdy said:
:(
I Know this might sound silly..
But Right know in our schools we are having a 2-weeks Christmas break,, After it directly, we have Pre-Mock examinations..
I have maths first day, I cant seem to be in contact with my teacher,,,
I need to know how to find F-1 (x )
the F inverse x !!!
..
Kindly..



oh so all u have to do is write the eqn of f(x) in terms of x and y
then make x the subject ....now replace y with x,,,,,this is f-1(x)

Eg: f(x) = 3x - 2 ...find f-1 (x)

---solution---

y = 3x - 2

y + 2 = 3x

x = (y + 2)/3

f-1(x) = (x + 2)/3


hope u got it now :)
 
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