Mathematics: Post your doubts here!

[stubborn angel]

i need maths core revision guide can any1 help me in tht??

 

[AmyyG]

Can anybody help me to resolve the exercise number 4 from maths exame summer 2009 pure maths 1 please? Thanks a lot

 

[WSK]

Anyone Please can email me ([email protected]) the Conversion notes for Maths
like a place where everything is written for Eg: 1cm= 1/100m something like that Please please

 

[amirjalili]

how do u find the 2 by 2 matrix from a given transformation ???????????????
pleeeeeeeeeeease someone help!!!!!!

 

[Cute-princesa]

Can any1 tell me about the curve on oct/nov 2011 for math
I want to know for both paper2 & 4 ..
Plz reply me asap
Tnx

 

[slayer]

HI, I was practicing some math past papers and Iam stuck on Q17 summer 2007 http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s07_qp_2.pdf please I need help ASAP! Thank you

 

[GetSomeLife]

HI, I was practicing some math past papers and Iam stuck on Q17 summer 2007 http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s07_qp_2.pdf please I need help ASAP! Thank you

(a) (32)^(1/2) means "Square root of 32"

(32)^(1/2) = 2^p

(2^5)^(1/2) = 2^p

2^[5*(1/2)] = 2^p

2^(5/2) = 2^p

Since the bases are same:

p = 5/2

(b) (1/8)^(1/3) means "Cube root of (1/8)"

(1/8)^(1/3) = 2^q

[1/(2^3)]^(1/3) = 2^q

(2^-3)^(1/3) = 2^q

2^[(-3)*(1/3)] = 2^q

2^-1 = 2^q

Since the bases are same:

q = -1

 

[slayer]

Thanks for the replay but may I ask u how did u know that 1/(2^3) = 1/8 :s

 

[Sarah.]

Can someone post all the conversions we need to learn for maths? PLEAAAAASE.

 

[Moar]

Thanks for the replay but may I ask u how did u know that 1/(2^3) = 1/8 :s

dude 2^3 = 8 (2*2*2) you can try it using a calculator. You really need to study indices mate.

 

[Yousif Mukkhtar]

Hey guys, I am having a question in MJ 06 Paper 2, question 14. Here is the link:
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s06_qp_2.pdf

The question is:
14 A company makes two models of television.
Model A has a rectangular screen that measures 44 cm by 32 cm.
Model B has a larger screen with these measurements increased in the ratio 5:4.
(a) Work out the measurements of the larger screen.

How can I get the measurements of the larger screen?

 

[Moar]

Hey guys, I am having a question in MJ 06 Paper 2, question 14. Here is the link:
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s06_qp_2.pdf

The question is:
14 A company makes two models of television.
Model A has a rectangular screen that measures 44 cm by 32 cm.
Model B has a larger screen with these measurements increased in the ratio 5:4.
(a) Work out the measurements of the larger screen.

How can I get the measurements of the larger screen?

Look the easiest way to think of it is this way:
5:4= 5/4 . so when you multiply 5/4 * each measurement it will give you the larger measurement.
5/4 * 44 = 55
5/4 * 32 = 40

 

[Yousif Mukkhtar]

Look the easiest way to think of it is this way:
5:4= 5/4 . so when you multiply 5/4 * each measurement it will give you the larger measurement.
5/4 * 44 = 55
5/4 * 32 = 40

Thanks a lot! You made it so simple for me.

 

[Yousif Mukkhtar]

Can some one help me in question number 15 (b):
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w06_qp_2.pdf
f: x
I----------> 5 − 3x

(b) Find f^-1(x)

 

[Moar]

Can some one help me in question number 15 (b):
http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w06_qp_2.pdf
f: x
I----------> 5 − 3x

(b) Find f^-1(x)

Ok... When you are dealing with functions and you want the inverse of a function (i.e : 5-3x) , you have to do the following :
1- change f:x into Y. So it will be y=5-3x
2-make x the subject : y-5=3x(moved 5 to the other side )
so x= y-5/3
3- Final step is change x to F^-1 (x) (the letter doesn't have to be F it can vary according to the question) , and change any x's into Y.
So here the answer will be F^-1 (x) = x-5/3
Btw what grade are you, i am assuming you are pre-IG right?

 

[Yousif Mukkhtar]

Ok... When you are dealing with functions and you want the inverse of a function (i.e : 5-3x) , you have to do the following :
1- change f:x into Y. So it will be y=5-3x
2-make x the subject : y-5=3x(moved 5 to the other side )
so x= y-5/3
3- Final step is change x to F^-1 (x) (the letter doesn't have to be F it can vary according to the question) , and change any x's into Y.
So here the answer will be F^-1 (x) = x-5/3
Btw what grade are you, i am assuming you are pre-IG right?

Grade 10 lol. Doing my final IGCSE this year.

 

[Yousif Mukkhtar]

Ok... When you are dealing with functions and you want the inverse of a function (i.e : 5-3x) , you have to do the following :
1- change f:x into Y. So it will be y=5-3x
2-make x the subject : y-5=3x(moved 5 to the other side )

Shouldn't it be y-5=-3x?

 

[Moar]

Shouldn't it be y-5=-3x?

Oh yeah lol , u are right , srry i am a bit sick today
so yes y-5= -3x and F^-1(X) = y-5/-3

 

[Moar]

But dude btw you should be knowing functions and these stuff before going into the exam. I suggest you give a quick look into math notes ​

 

[Yousif Mukkhtar]

But dude btw you should be knowing functions and these stuff before going into the exam. I suggest you give a quick look into math notes ​

My good friend, I already know all of this function calculations. I even answered exactly what you just did.

I think you and I both made a mistake. In the mark scheme the answer is (5-x)/3

I did exactly what you just did but got a different answer from the mark scheme. Because I too got x-5/-3

Actually, I believe there is something wrong with the mark scheme.