- Messages
- 4,152
- Reaction score
- 12,461
- Points
- 523
15:
Area of smaller triangle/area of larger triangle = [length of smaller triangle/length of larger triangle]^2
11/99 = (BC/12)^2
11/99 = BC^2/144
BC^2 = 1/9 * 144 = 16
BC = 16^(1/2)
BC = +- 4
Since length can't be negative
BC = 4 cm
18:
a) Pythagoras theorem:
Let the distance be 'x'
x^2 = 83^2 + 78^3
Simplify:
x = 113.8990781
x = 114
b) Let the bearing be (90 - y)
Tan y = Opposite/adjacent
y = Tan inverse (78/83)
y = 43.2
Bearing = 90 - y = 46.8 = 047 degrees