Mathematics: Post your doubts here!

[PhyZac]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_42.pdf
question 1 part b
question3 part b
question7 part a
plz reply me im posting bt everyone ignorning my post plz for sake of ALLAH REPLY

1 (b) ( 3.5 / 100 ) * 7500 * 5 = 1312.5
1312.5 + 7500 = 8812.5

3 (b) tan ( x) = 1.7/2.5
tan ^-1 ( 1.7/2.5 ) =34.2

7 ( a)[ 2.5 * 2.5 * sin ( 60) *0.5 *6 ] + [ 9.5*2.5*0.5*6] = 87.5

 

[Lost_Life]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_41.pdf
QUESTION 6 PART B PLZ REPLY FOR SAKE OF ALLAH

just add all the faces, you have two triangles so you multiply 2 the area of 1 traingle
1/2 *14*19 =Ans *2 then you find the area of the rectangle (bottom)
14*36
then find the other rectangle19*36
then The side 23.6*36
Add them all up and youll get 2303
hope that helps

 

[rjcooo1]

I need help asappp!!

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_42.pdf
number 10 pleasee

 

[NIM]

I don't understand this... :/
isn't there another way of solving it??

i hav seen this type of question in some other past paper (22)...
bt unfortunately i hav forgotten the method of solving.....

 

[NIM]

I need help asappp!!

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_42.pdf
number 10 pleasee

whole or any part....

 

[NIM]

10 c i)
1/P 3(3-q)=0
1/P 4(4-q)=2 .... (4 is the second number of sides and 2 is the total number of diagonals)...
put 3 in the place of q
1/p 4(4-3)=2
4/P = 2
2P=4
P=2
for Q
9-3q=0
3q=9
q=9/3
q=3.....
so P=2 and q=3...
em so bad in explaining...
so i hope u got it.......

 

[NIM]

10d..
1/2 n(n-3)=30+1/2(n+1)(n+1-3)

 

[сᴏᴏʟ сяуѕтᴀʟѕ]

I need help asappp!!

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s10_qp_42.pdf
number 10 pleasee

Assalam-o-alaikum wr wb..

 

[anooshraja]

just add all the faces, you have two triangles so you multiply 2 the area of 1 traingle
1/2 *14*19 =Ans *2 then you find the area of the rectangle (bottom)
14*36
then find the other rectangle19*36
then The side 23.6*36
Add them all up and youll get 2303
hope that helps

thanks alot MAY ALLAH BLESS U

 

[anooshraja]

1 (b) ( 3.5 / 100 ) * 7500 * 5 = 1312.5
1312.5 + 7500 = 8812.5

3 (b) tan ( x) = 1.7/2.5
tan ^-1 ( 1.7/2.5 ) =34.2

7 ( a)[ 2.5 * 2.5 * sin ( 60) *0.5 *6 ] + [ 9.5*2.5*0.5*6] = 87.5

THANKS ALOT MAY ALLAH BLESS YOU SORRY BT CAN U SEE QUESTION 3 AGAIN THANK YOU

 

[Abdelrahman Amr]

plz help last question paper4/nov11/43/last part

 

[NIM]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_42.pdf
question 1 part b
question3 part b
question7 part a
plz reply me im posting bt everyone ignorning my post plz for sake of ALLAH REPLY

dude for question 1 part b use simple interest formula
simple interest = PRT/100
7500*3.5*5/100
the answer u r going to hav will be 1312.5..
add 7500 into 1312.5 which will be 8812.5....
for question 3 part b...
first of all u hav to calculate the time taken by subtracting 11:57 from 14:12
answer will be 2.25....
1500/2.25
u will get 666.67....
and dude for the last one i hav to think abut that!!!!!!!!!!
i hope u get it

 

[NIM]

Yea, even I saw it in 22 in the 2005 paper I think...
But what if it ends up coming in the exam, then how will u do it??

no idea !!!
just pray from God it wont come!!!!

 

[anooshraja]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_43.pdf
QUESTION iv and v
partbii,iii,iv and v
plz for sake of ALLAH TANKYOU

 

[GetSomeLife]

For now that's all I can do! But it'll be of great help if anyone could tell me a way of doing questions like these...

Which question?

 

[anooshraja]

plz help last question paper4/nov11/43/last part

WHICH QUESTION

 

[GetSomeLife]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_43.pdf
QUESTION iv and v
partbii,iii,iv and v
plz for sake of ALLAH TANKYOU

Which question

 

[NIM]

For now that's all I can do! But it'll be of great help if anyone could tell me a way of doing questions like these...

exactly.........

 

[GetSomeLife]

exactly.........

I ask again: Which question?

 

[anooshraja]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_s11_qp_43.pdf
QUESTION 11 iv and v
partbii,iii,iv and v
plz for sake of ALLAH TANKYOU