Mathematics: Post your doubts here!

[aliiiiiiiiii]

Mode: 11 (because it has the highest frequency)
Median: 12+13/2 = 12.5
Mean = (11*35 + 12*28 + 13*22 + 14*18 + 15*14 + 16*9)/(35 + 28 + 22 + 18 + 14 + 9) = 12.8

Median: 12+13/2 = 12.5
shouldnt it be 13+14/2

 

[shefali]

Thank you so much I actually get it now and it feels good!



I don't understand logs cuz it's not in the igcse mathematics extended syllabus! But thank you for trying to help!

Your welcome I haven't done log either just know the basic..it saves a lot of time though anyways good luck..you'll get A*

 

[GetSomeLife]

Median: 12+13/2 = 12.5
shouldnt it be 13+14/2

Nopes. The two numbers you get are 63 (which comes under 12) and 64(which comes under 13)

 

[Lost_Life]

guys, stop practicing.....you had 2YEARS TO PRACTICE
just relax breath and pray
pray for the best
get some sleep
be well and ready before the exam

 

[nolife4now]

getsomelife stop answering all the questions iam getting bored

 

[aliiiiiiiiii]

Nopes. The two numbers you get are 63 (which comes under 12) and 64(which comes under 13)

thanx very much

 

[GetSomeLife]

thanx very much

Anything for my followers

 

[Hamzeh S]

negative shear simply moves to the left side instead of right
Transformations:http://www.gcsemathstutor.com/transformations.php
http://www.s-cool.co.uk/gcse/maths/transformations/revise-it/transformations

Well i had a questions which the point was at (-1 , 1) and moved to (-1,2) it was shear y axis invarient but the scale factor was -1 why :S ?

 

[JimmyCarter]

Please i want your help. When you are given a bunch of inequalities and you draw them and you shade the unwanted regions. How do you find for example the least possible cost (if the inequalities represent number of boxes) of total boxes? this was a question in october november 2011 paper 43 question 10 please check it out and inform me how




Thanks in Advaaance!!!
Ladies and gentlemen!!

 

[Hamzeh S]

Please i want your help. When you are given a bunch of inequalities and you draw them and you shade the unwanted regions. How do you find for example the least possible cost (if the inequalities represent number of boxes) of total boxes? this was a question in october november 2011 paper 43 question 10 please check it out and inform me how




Thanks in Advaaance!!!
Ladies and gentlemen!!

just take the points in the corners of the unshaded area (the regions he wants ) then make a table put the x's and y's of the corners and multiply it by the amount given for y and x and find the highest or lowest cost

 

[JimmyCarter]

just take the points in the corners of the unshaded area (the regions he wants ) then make a table put the x's and y's of the corners and multiply it by the amount given for y and x and find the highest or lowest cost

I thought about doing that but then i figured why would the question be for only 1 mark and with so little space? but if thats the way then thankk you so much!! Wish you the best!

 

[sma786]

http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s10_qp_42.pdf

Help ! Question 10, (c ,i)

 

[RoyalPurple]

(1/p)4(4-q)=2 solve it u'll get an equ

(1/p)5(5-q)=25 slove u'll get 2nd equ

finally,solve simultaneously

 

[JimmyCarter]

http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s10_qp_42.pdf

Help ! Question 10, (c ,i)

Hey! so what you need to do is equate the equation to forexample the number of diagonals of a pentagon and a hexagon (u can easily find the diagonals by just drawing them) and you will have two simultaneous equations that you can easily solve.

All the best honey

 

[Maz]

Thank you!
Good luck to you too and I'll pray you get an A* as well!

I know I am sending this too late.However, i found this in the examiner's report

Very few candidates scored this single mark. h(x) maps a value in one set onto a specific value in
a second set; h−1(x) reverses the process and maps the second value back onto the first. So if
h−1(x) = 2, the “2” has come from h(2) = 9. The function h−1(x) need not be considered.

 

[slayer]

guys please I need help ASAP!! Q2aiii http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w09_qp_4.pdf how do we get the center on enlargement?!

 

[chaotic]

@slayer
very easy, draw a line (that covers all the the graph) between a point in the triangle and it's corresponding point in the image, then do it again with another point in the triangle and it's corresponding point in the image, the two lines you drew intersects at a point, this point is the center

in your question:
draw a line between (3,1), (-3,-5) (extend to cover all the graph)
draw a line between ( 6,3), (6,1) (extend to cover all the graph)
center: (6,4)

maybe not the best way, but with a little of common sense, it always work (atleast with positive enlargements)

EDIT: if someone have a better way, share please, i do have a faster way but it's error prone (and so i used the line drawing way)

 

[Maz]

Ok, so I was freaking myself out when all I had to do was ignore the inverse... -.-
But thank you so much! This was actually REALLY helpful!
Good luck!

i know reading it, makes it look so easy. but i am wondering whether is it always the case that the
answer of an inverse is the value in the brackets.

 

[slayer]

@slayer
very easy, draw a line (that covers all the the graph) between a point in the triangle and it's corresponding point in the image, then do it again with another point in the triangle and it's corresponding point in the image, the two lines you drew intersects at a point, this point is the center

in your question:
draw a line between (3,1), (-3,-5) (extend to cover all the graph)
draw a line between ( 6,3), (6,1) (extend to cover all the graph)
center: (6,4)

maybe not the best way, but with a little of common sense, it always work (atleast with positive enlargements)

EDIT: if someone have a better way, share please, i do have a faster way but it's error prone (and so i used the line drawing way)

Thank you I really appreciate you work!!

 

[za Shadow]

hey guys PLZZZZZZ NEEDDDDDD URGENT HELP!!!! EXAM TOMORROW

give me any HELP ME WITH SEQUENCE

TELL ME ANYTHING THAT COULD HELP ME TO SOLVE ANY SEQUENCE QUESTION NO MATTER HOW HARD IT IS PLZZZZZZZZZZZZZ