• We need your support!

    We are currently struggling to cover the operational costs of Xtremepapers, as a result we might have to shut this website down. Please donate if we have helped you and help make a difference in other students' lives!
    Click here to Donate Now (View Announcement)

Mathematics: Post your doubts here!

Messages
29
Reaction score
0
Points
0
abcde said:
sspigcse said:
i have a doubt in the transformation matrices and my exam is on monday please help me with the topic.
Also ae there any formula for quadratic sequence.
AoA!
For help on transformation matrices, please check my previous post here.
The formula to find the nth term of a quadratic sequence is: a + (n - 1)d1 + 1/2 (n - 1)(n - 2)d2 ,
where: a is the 1st term of the sequence
d1 is the difference b/w the first two terms of the sequence
d2 is the constant difference b/w any two terms of the derived sequence.
you can thank me for the formula :p
 
Messages
1,594
Reaction score
483
Points
93
sspigcse said:
abcde said:
sspigcse said:
i have a doubt in the transformation matrices and my exam is on monday please help me with the topic.
Also ae there any formula for quadratic sequence.
AoA!
For help on transformation matrices, please check my previous post here.
The formula to find the nth term of a quadratic sequence is: a + (n - 1)d1 + 1/2 (n - 1)(n - 2)d2 ,
where: a is the 1st term of the sequence
d1 is the difference b/w the first two terms of the sequence
d2 is the constant difference b/w any two terms of the derived sequence.
you can thank me for the formula :p
How come? Elucidate!
 
Messages
44
Reaction score
5
Points
18
can any one plz tell me the matrix of shear and stretch......
m little bit confused :( :( :( :(
 
Messages
4
Reaction score
0
Points
1
Yeah i just wanted to ask if u really lost marks for not putting ur answers to 3sf, because i didnt.
My teacher didnt tell me and i didnt read the cover.
So am i screwed?
Also howmany marks u think i lost in total?
 
Messages
892
Reaction score
168
Points
38
I have a problem in Add Maths,
Trignometry

cos.png


I have successfully solved the question till a point,
but after taking out value of "alpha",
as cos(z + π/6)= - 1/2
So it should be in 2nd quadrant or 3 quadrant.

In the marking scheme, they have solved for 1 and 4th quadrant.

I havent done trig in a long time,
Can anyone explain why we will find values of quadrant 1 and 4, which are actually positive, and not 2 and 3, which are negative.

P.S: to write symbol of "pie" (π), turn on the numlock, keep alt key pressed, and then write "227" in the numpad.
Or you can simply copy paste it from my post..
 
Messages
38
Reaction score
9
Points
18
princex said:
i d0nt understand bearing plz help..!!!
:(

Without a question, it is hard to answer your doubt specifically. However, in general, Bearing is nothing but angles, in combination of Pythagoras Theorem in certain aspects. The main thing to keep in mind is that when measuring Bearings, you have to always start from the North of the object, and then go clock-wise. Moreover, the value of any Bearing must be 3 digits, e.g: 065 degree. Those are the basic rules.
 
Messages
8,392
Reaction score
9,461
Points
573
Martee100 said:
Could somebody help me in this?

http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s02_qp_2.pdf

Q14 part B especially! :D Thanks 8)
This one is easy!
ok so in part b we are given that y < -1
thus therefore we know that all the values of y are less then -1.
therefore to arrange it in increasing order
first number will be y^3 as its the smallest. just choose 1 number and keep on using that number throughout the pattern. If we have choosed y=-1 then y^3 = -3.
then for the next y^-1 = -1^-1 and that = -1
for the next y^0 = -1^0 = 1
so now the arrangement will be the following
y^3, y^-1, y^0, y^2.
 
Messages
247
Reaction score
373
Points
73
SalmanPakRocks said:
Martee100 said:
Could somebody help me in this?

http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s02_qp_2.pdf

Q14 part B especially! :D Thanks 8)
This one is easy!
ok so in part b we are given that y < -1
thus therefore we know that all the values of y are less then -1.
therefore to arrange it in increasing order
first number will be y^3 as its the smallest. just choose 1 number and keep on using that number throughout the pattern. If we have choosed y=-1 then y^3 = -3.
then for the next y^-1 = -1^-1 and that = -1
for the next y^0 = -1^0 = 1
so now the arrangement will be the following
y^3, y^-1, y^0, y^2.

Ok one more question its not y ≤ -1 , it is y < -1 so we cant take -1 right as its not equal, moreover can use any other number other than -1 and show me another example I am really confused! Thanks alot dude! 8)
 
Messages
8,392
Reaction score
9,461
Points
573
yes if then we can take y < -1 anyways I will, but right now a little busy. U try and post ur solution here and i'll check it.! :)
 
Top