Mathematics: Post your doubts here!

[SalmanPakRocks]

please post the link of the paper

 

[sspigcse]

it is pretty easy wen it comes to maths just a bit of logic!!

 

[sspigcse]

i have a doubt in the transformation matrices and my exam is on monday please help me with the topic.
Also ae there any formula for quadratic sequence.

AoA!
For help on transformation matrices, please check my previous post here.
The formula to find the nth term of a quadratic sequence is: a + (n - 1)d1 + 1/2 (n - 1)(n - 2)d2 ,
where: a is the 1st term of the sequence
d1 is the difference b/w the first two terms of the sequence
d2 is the constant difference b/w any two terms of the derived sequence.

you can thank me for the formula

 

[abcde]

i have a doubt in the transformation matrices and my exam is on monday please help me with the topic.
Also ae there any formula for quadratic sequence.

AoA!
For help on transformation matrices, please check my previous post here.
The formula to find the nth term of a quadratic sequence is: a + (n - 1)d1 + 1/2 (n - 1)(n - 2)d2 ,
where: a is the 1st term of the sequence
d1 is the difference b/w the first two terms of the sequence
d2 is the constant difference b/w any two terms of the derived sequence.

you can thank me for the formula

How come? Elucidate!

 

[sspigcse]

i posted the same thing before ya @abcde

 

[abcde]

i posted the same thing before ya @abcde

I missed that. Why ask if you knew the formula already?

 

[valeloud]

I have some doubts on q 5 e) , and 10 c)ii) on paper 4 november 2008. I appreciate if anyone can explain this because i have my test on monday. Thank you.
http://www.xtremepapers.com/CIE/Cambrid ... _qp_04.pdf. My test is tomorrow so i really need to understand this.

 

[angel786]

can any one plz tell me the matrix of shear and stretch......
m little bit confused

 

[890xyzn]

Yeah i just wanted to ask if u really lost marks for not putting ur answers to 3sf, because i didnt.
My teacher didnt tell me and i didnt read the cover.
So am i screwed?
Also howmany marks u think i lost in total?

 

[Anon]

I have a problem in Add Maths,
Trignometry

I have successfully solved the question till a point,
but after taking out value of "alpha",
as cos(z + π/6)= - 1/2
So it should be in 2nd quadrant or 3 quadrant.

In the marking scheme, they have solved for 1 and 4th quadrant.

I havent done trig in a long time,
Can anyone explain why we will find values of quadrant 1 and 4, which are actually positive, and not 2 and 3, which are negative.

P.S: to write symbol of "pie" (π), turn on the numlock, keep alt key pressed, and then write "227" in the numpad.
Or you can simply copy paste it from my post..

 

[Anon]

.
I got my mistake,

 

[princex]

i d0nt understand bearing plz help..!!!

 

[SalmanPakRocks]

i d0nt understand bearing plz help..!!!

please post a particular question so I may be able to help u.
P.S Bearings is VERY easy.

 

[Spirit95]

i d0nt understand bearing plz help..!!!

Without a question, it is hard to answer your doubt specifically. However, in general, Bearing is nothing but angles, in combination of Pythagoras Theorem in certain aspects. The main thing to keep in mind is that when measuring Bearings, you have to always start from the North of the object, and then go clock-wise. Moreover, the value of any Bearing must be 3 digits, e.g: 065 degree. Those are the basic rules.

 

[nabil456]

hey i am facing problem in thiz papers last question i dont understand it http://www.xtremepapers.com/CIE/Cambrid ... 8_qp_4.pdf Q 10 plz help

 

[Martee100]

Could somebody help me in this?

http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s02_qp_2.pdf

Q14 part B especially! Thanks 8)

 

[SalmanPakRocks]

Could somebody help me in this?

http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s02_qp_2.pdf

Q14 part B especially! Thanks 8)

This one is easy!
ok so in part b we are given that y < -1
thus therefore we know that all the values of y are less then -1.
therefore to arrange it in increasing order
first number will be y^3 as its the smallest. just choose 1 number and keep on using that number throughout the pattern. If we have choosed y=-1 then y^3 = -3.
then for the next y^-1 = -1^-1 and that = -1
for the next y^0 = -1^0 = 1
so now the arrangement will be the following
y^3, y^-1, y^0, y^2.

 

[princex]

i d0nt understand bearing plz help..!!!

please post a particular question so I may be able to help u.
P.S Bearings is VERY easy.

oki ill tell u

 

[Martee100]

Could somebody help me in this?

http://www.xtremepapers.com/CIE/Cambridge IGCSE/0580 - Mathematics/0580_s02_qp_2.pdf

Q14 part B especially! Thanks 8)

This one is easy!
ok so in part b we are given that y < -1
thus therefore we know that all the values of y are less then -1.
therefore to arrange it in increasing order
first number will be y^3 as its the smallest. just choose 1 number and keep on using that number throughout the pattern. If we have choosed y=-1 then y^3 = -3.
then for the next y^-1 = -1^-1 and that = -1
for the next y^0 = -1^0 = 1
so now the arrangement will be the following
y^3, y^-1, y^0, y^2.

Ok one more question its not y ≤ -1 , it is y < -1 so we cant take -1 right as its not equal, moreover can use any other number other than -1 and show me another example I am really confused! Thanks alot dude! 8)

 

[SalmanPakRocks]

yes if then we can take y < -1 anyways I will, but right now a little busy. U try and post ur solution here and i'll check it.!