Mathematics: Post your doubts here!

[darklashbazinga]

Try going backwards starting with the latest paper available, do all the variants.

can u be a little more sprcific like how many years back??????plzzzzz

 

[darklashbazinga]

Try going backwards starting with the latest paper available, do all the variants.

could u also plzzzzz post all the formulas of volumes areas similarity ,etc(in short all formulas) plzz it would help me a lot
thanx

 

[XPFMember]

can u be a little more sprcific like how many years back??????plzzzzz

it's better if u do till 2002 but try atleast till2005

formulas i don't have any stuff now...did 2 yrs back

 

[MidnightHolly]

When would the May 2012 papers be uploaded? I am giving my IGCSE this November and need to know the latest paper patterns!

 

[Prathmesh Thakkar]

A person has a set oh hoilday photoz (fewer than a 100) which she will put in an album.
If she puts 2 photos on a page 1 photograph is left over.
If she puts 3 photos on a page 2 photograph is left over.
If she puts 4 photos on a page 3 photograph is left over.
If she puts 5 photos on a page 4 photograph is left over.
How many photos does she have in total.?
You should show all your working........[5 marks]
-IGCSE MAthematics

 

[Prathmesh Thakkar]

When would the May 2012 papers be uploaded? I am giving my IGCSE this November and need to know the latest paper patterns!

dey are olredy out.......olevelsourceforge.net

 

[i-copeland]

How do you do this...

17. (c) AB is the diameter of a circle, centre O. C, D and E lie on the circle.

EC is parallel to AB and perpendicular to OD. Angle DOC is 38°.​

Work out angle EDO .​

I got it from here: 0580_s10_qp_21.pdf

 

[Saahil Parikh]

How do you do this...

17. (c) AB is the diameter of a circle, centre O. C, D and E lie on the circle.

EC is parallel to AB and perpendicular to OD. Angle DOC is 38°.​

Work out angle EDO .​

I got it from here: 0580_s10_qp_21.pdf

its 71 right?

 

[i-copeland]

That's i think what the mark scheme says, but can u explain how? Thanks.

 

[Saahil Parikh]

That's i think what the mark scheme says, but can u explain how? Thanks.

angle oec is 38/2= 19( angle at circumference = 1/2 * angle at centre..)
hence angle edo= 180-(90+19) = 180-109= 71

 

[i-copeland]

angle oec is 38/2= 19( angle at circumference = 1/2 * angle at centre..)
hence angle edo= 180-(90+19) = 180-109= 71

I found another way. (troll got trolled?)

 

[msn201]

Guyz how to do we solve question number 6 june 2011 paper 21?

 

[ayesha1429]

I need notes that explain me Histograms ... Anyone ? Pleeeease ?

 

[2012101]

Assalamoalaikum!!

Stuck somewhere in Maths?? Post your queries here! If you have any doubt in the pastpper questions, then kindly post the link to the paper!

P.S. I'm busy these days, so I can't promise to be there for help.

May Allah give us all success in this world as well as the HereAfter...Aameen!!

SEQUENCES-Points to remember:
Many people find it hard, but to be honest it's just more of logic..that's all!

Sequences!

Using log for indices.

Some help here.
The two equal sides of an isosceles triangle are each 5cm long and the third side is 8cm. Calculate the area.

 

[AAnsarii]

http://www.xtremepapers.com/papers/CIE/Cambridge IGCSE/Mathematics (0580)/0580_w06_qp_4.pdf
7 a i. hw do u solve dat?

 

[XPFMember]

Some help here.
The two equal sides of an isosceles triangle are each 5cm long and the third side is 8cm. Calculate the area.

AOA!

Well...divide the triangle into half....such that you get 2 equal right angled triangle..

te 8cm side wud be divided into two 4cm bases of the right angled triangle

find the height of the right angled triangle..using pythagoras theorem

and then find the area...

 

[AAnsarii]

Some help here.
The two equal sides of an isosceles triangle are each 5cm long and the third side is 8cm. Calculate the area.

 

[AAnsarii]

Guyz how to do we solve question number 6 june 2011 paper 21?

small=2cm large= 6cm
so, ratio= 2:6
= 1:3

small large
1 3
4 x
[cross multiply]

x = 4*3
x = 12g

 

[2012101]

Thank you very much

 

[2012101]

Thank you very much