Mathematics: Post your doubts here!

[Amy Bloom]

Hello amyhiii!!!!!!!1hi how are you???
its e^x=0 which u said it and the other one should be 6-3e^2x=0 when u solve it...............................
and hey @shanki631 its a maximum point on the curve where x=0.427...........................????is it correct?

Err What? I don't get u. I wanted to substitute e^x by y for it to be easier to solve.

 

[Amy Bloom]

Hey and do u want me to attach a scan???or u will do it?

I'm just sending off some ideas to help shanky to do it. U can send urs or solve it completely for him if u wish.

 

[Amy Bloom]

I guess u may have pressed the media button but its the button of upoload a file on the right hand side under the dialog box in which u are now typing,,,,,,,,,,,,,

I usually do my drawings on paint, coz my scanner's got some problem at the moment and can't work. it says that it cannot upload a bitmap image. How can i upload an image anyways?

 

[parthrocks]

I'm just sending off some ideas to help shanky to do it. U can send urs or solve it completely for him if u wish.

But you are more experienced as I know.....You are a genious!!

 

[parthrocks]

I usually do my drawings on paint, coz my scanner's got some problem at the moment and can't work. it says that it cannot upload a bitmap image. How can i upload an image anyways?

Ohhh ya see the document that u made....the paint file open it...and then click save as and then save it as format:-JPEG and then upload it only then it will get uploaded.................BITMAP files are not allowed here

 

[Amy Bloom]

But you are more experienced as I know.....You are a genious!!

I'm neither genius nor robot. Just a simple student.

 

[parthrocks]

I'm neither genius nor robot. Just a simple student.

Ya I agree with that!!!lolzzzzzzzzzzzzz

 

[Amy Bloom]

Ohhh ya see the document that u made....the paint file open it...and then click save as and then save it as format:-JPEG and then upload it only then it will get uploaded.................BITMAP files are not allowed here

Okay thanks.

 

[shanky631]

Hello amyhiii!!!!!!!1hi how are you???
its e^x=0 which u said it and the other one should be 6-3e^2x=0 when u solve it...............................
and hey @shanki631 its a maximum point on the curve where x=0.427...........................????is it correct?

the ans is o.35

 

[parthrocks]

the ans is o.35

Ya is it 0.3465735903???

 

[shanky631]

Ya is it 0.3465735903???

ya dude now plz attach scan na

 

[parthrocks]

ya dude now plz attach scan na

Is it ok if I attach at 6:45 or 7:00 pm..???cos my ipod is with my sis!!ok

 

[shanky631]

in part b of the same question, did u get maximum bcoz the value is around -16.99??

 

[parthrocks]

in part b of the same question, did u get maximum bcoz the value is around -16.99??

Rounding it off as 0.347 ya correct u got that cool

 

[parthrocks]

Rounding it off as 0.347 ya correct u got that cool

So no need of scan now na?

 

[parthrocks]

plzzz 10,11,12 and 13th question solve and aTTACH AS A SCAN PLZZZZZZZZZZ if possibel or work it out here

 

[celoth]

http://www.mediafire.com/view/?o2cp74d0881nbb9#
this is the link to differentitaing trignometric function chapter 6 in p2 and p3 i have a doubt in exercise 6a question number 6,question 7 and question 8 part a and part e.......
and also question 9 part b and f........................plzzzzzzzzzzzzzz reply asap...its just a few question.....plz attach scan!!
smzimran
minato112
celoth
plzzz help me asap

the image is kinda blur,
I can't see the question clearly,
just answer according to what i am able to see @_@,

6a) ans : (cos x)exp(sin x)

6b) ans : -3(sin 3x)exp(cos 3x)

6c) ans : 10(sin x)(cos x)exp(sin^2 x)

whenever you need to differentiate exponential thing,
like exp(u) , where u is another function in x,
the answer is (du/dx)exp(u).

i will solve the rest if got time

 

[parthrocks]

plzzz 10,11,12 and 13th question solve and aTTACH AS A SCAN PLZZZZZZZZZZ if possibel or work it out here

celoth help me with this first nowwwwwwwwwwwwwwwwwwww

 

[celoth]

plzzz 10,11,12 and 13th question solve and aTTACH AS A SCAN PLZZZZZZZZZZ if possibel or work it out here

no 10)
1st method: Chain rule:

Let u=a+x, du/dx=1
therefore, y=sin u, dy/du=cos u

by chain rule,
dy/dx
= dy/du x du/dx
= cos u x 1
= cos u
= cos (a+x)

2nd method: expansion:

sin(a+x) = (sin a)(cos x)+(cos a)(sin x)

dy/dx
= -(sin a)(sin x)+(cos a)(cos x)
= (cos a)(cos x)-(sin a)(sin x)
= cos (a+x)

the answer is same for both methods

 

[parthrocks]

no 10)
1st method: Chain rule:

Let u=a+x, du/dx=1
therefore, y=sin u, dy/du=cos u

by chain rule,
dy/dx
= dy/du x du/dx
= cos u x 1
= cos u
= cos (a+x)

2nd method: expansion:

sin(a+x) = (sin a)(cos x)+(cos a)(sin x)

dy/dx
= -(sin a)(sin x)+(cos a)(cos x)
= (cos a)(cos x)-(sin a)(sin x)
= cos (a+x)

the answer is same for both methods

and what about 11th question?