Mathematics: Post your doubts here!

[Danyal Abbasi]

I just completed IGCSE and took "C" in mathematics. I have opted for the same subject in A'levels and I am not confident at all. Can I practically think of achieving an A grade in A'levels. I am really weak.

 

[bamteck]

http://www.xtremepapers.com/papers/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_w03_qp_4.pdf

Please someone help me for Nov 2003 P4 M1 no. 6(ii) & 7(iv)
Thanks

 

[iKhaled]

I just completed IGCSE and took "C" in mathematics. I have opted for the same subject in A'levels and I am not confident at all. Can I practically think of achieving an A grade in A'levels. I am really weak.

grade C in mathematics IGCSE, which is basic stuff means u will hardly achieve a D or an E in mathematics A levels. can u build a building if u didn't build the base properly ? that's the same as ur situation...

 

[parthrocks]

How to solve x^6 -12x^2+16=0
the answer is
± root
2 , ± 2i
how???help
smzimran
leadingguy

nightrider1993
reply soon with the working attach here if possible plzzzzzzzzzzzzzzzzzzzzzzzzzz

 

[parthrocks]

(ii)
Sketch an Argand diagram showing the locus of the complex number s such that |s − u| = |u|
.
[3]
show me how the argand diagram looks!!
smzimran plzzzzzzzzz

 

[shanky631]

plz can someone solve this question.

 

[lovelymimi]

http://www.xtremepapers.com/papers/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_13.pdf
Q6 plzz help

T3=20
ar2=20
a=20/r2


sum to infinity=3a
a/(1-r)=3a
a=3a(1-r)
20/r2=3(20/r2)(1-r)
20/r2=60/r2(1-r)
60-60r=20
-60r=20-60
-60r=-40
r=2/3

a=20/(2/3)2
=45

T8=3T3
a+7d=3(a+2d)
45+7d=3(45)+6d
7d-6d=135-45
d=90

s8=4s4
s8=8/2[2(45)+7(90)]
=2880

s4=4/2[2(45)+3(90)]
=720
s8=4s4
2880=4(720)
2880=2880
(hence shown)

 

[parthrocks]

How to solve x^6 -12x^2+16=0
the answer is
± root
2 , ± 2i
how???help
smzimran
leadingguy

nightrider1993
reply soon with the working attach here if possible plzzzzzzzzzzzzzzzzzzzzzzzzzz

@leading guy
help me

 

[parthrocks]

How to solve x^6 -12x^2+16=0
the answer is
± root
2 , ± 2i
how???help
smzimran
leadingguy

nightrider1993
reply soon with the working attach here if possible plzzzzzzzzzzzzzzzzzzzzzzzzzz

@leading guy
help me

 

[parthrocks]

How to solve x^6 -12x^2+16=0
the answer is
± root
2 , ± 2i
how???help
smzimran
leadingguy

nightrider1993
reply soon with the working attach here if possible plzzzzzzzzzzzzzzzzzzzzzzzzzz

leadingguy
help sorry posted just one time bt due to some thing it came 3 times srry!!!everyone

 

[parthrocks]

How to solve x^6 -12x^2+16=0
the answer is
± root
2 , ± 2i
how???help
smzimran
leadingguy

nightrider1993
reply soon with the working attach here if possible plzzzzzzzzzzzzzzzzzzzzzzzzzz

Amy Bloom fast

 

[parthrocks]

(ii)
Sketch an Argand diagram showing the locus of the complex number s such that |s − u| = |u|
.
[3]
show me how the argand diagram looks!!
smzimran plzzzzzzzzz

Amy Bloom

 

[krishna]

http://www.xtremepapers.com/papers/...AS Level/Mathematics (9709)/9709_s05_qp_7.pdf
question 3 can anyone do it for me plz n thus a little explanation also!!

 

[hussamh10]

T3=20
ar2=20
a=20/r2


sum to infinity=3a
a/(1-r)=3a
a=3a(1-r)
20/r2=3(20/r2)(1-r)
20/r2=60/r2(1-r)
60-60r=20
-60r=20-60
-60r=-40
r=2/3

a=20/(2/3)2
=45

T8=3T3
a+7d=3(a+2d)
45+7d=3(45)+6d
7d-6d=135-45
d=90

s8=4s4
s8=8/2[2(45)+7(90)]
=2880

s4=4/2[2(45)+3(90)]
=720
s8=4s4
2880=4(720)
2880=2880
(hence shown)

thanx alot!!But how did u know that the first term of geometric progression is also the first term of an arthimetic?

 

[hussamh10]

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s10_qp_11.pdf
Q1 plzz help..
explain

 

[lovelymimi]

thanx alot!!But how did u know that the first term of geometric progression is also the first term of an arthimetic?[/quote

it is obvious the answer in(i) part need 2 be used in the second part in order 2 be able 2 solve it...

 

[bamteck]

Someone please help me :
The second term of a geometric progression is 3 and the sum to infinity is 12.
Find the first term of the progression.
[Quoted from June 07 p1]

Albert Einstein or leadingguy

 

[Minato112]

Someone please help me :
The second term of a geometric progression is 3 and the sum to infinity is 12.
Find the first term of the progression.
[Quoted from June 07 p1]

Second term of G.P = ar = 3 ----- (1)
Sum to infinity = a / (1 - r) = 12
=> a = 12 - 12r

From (1) r = 3/a

Therefore equating the 2 equations
a = 12 - 12(3/a)
a = (12a - 36)/a
a ^2 = (12a - 36)
a^2 - 12a + 36 = 0
(a - 6)(a - 6) = 0
a = 6

 

[bamteck]

Second term of G.P = ar = 3 ----- (1)
Sum to infinity = a / (1 - r) = 12
=> a = 12 - 12r

From (1) r = 3/a

Therefore equating the 2 equations
a = 12 - 12(3/a)
a = (12a - 36)/a
a ^2 = (12a - 36)
a^2 - 12a + 36 = 0
(a - 6)(a - 6) = 0
a = 6

Thank you very much mate

 

[Minato112]

Thank you very much mate

No prob!