Mathematics: Post your doubts here!

[lovelymimi]

thanx alot!!But how did u know that the first term of geometric progression is also the first term of an arthimetic?[/quote

it is obvious the answer in(i) part need 2 be used in the second part in order 2 be able 2 solve it...

 

[bamteck]

Someone please help me :
The second term of a geometric progression is 3 and the sum to infinity is 12.
Find the first term of the progression.
[Quoted from June 07 p1]

Albert Einstein or leadingguy

 

[Minato112]

Someone please help me :
The second term of a geometric progression is 3 and the sum to infinity is 12.
Find the first term of the progression.
[Quoted from June 07 p1]

Second term of G.P = ar = 3 ----- (1)
Sum to infinity = a / (1 - r) = 12
=> a = 12 - 12r

From (1) r = 3/a

Therefore equating the 2 equations
a = 12 - 12(3/a)
a = (12a - 36)/a
a ^2 = (12a - 36)
a^2 - 12a + 36 = 0
(a - 6)(a - 6) = 0
a = 6

 

[bamteck]

Second term of G.P = ar = 3 ----- (1)
Sum to infinity = a / (1 - r) = 12
=> a = 12 - 12r

From (1) r = 3/a

Therefore equating the 2 equations
a = 12 - 12(3/a)
a = (12a - 36)/a
a ^2 = (12a - 36)
a^2 - 12a + 36 = 0
(a - 6)(a - 6) = 0
a = 6

Thank you very much mate

 

[Minato112]

Thank you very much mate

No prob!

 

[Mad-Eye]

What does the syllabus say about Exponential and Logarithms in P3? Is the Exponential Growth and Decay part necessary?
Please help me ASAP if you can...
Thanx.

 

[parthrocks]

What does the syllabus say about Exponential and Logarithms in P3? Is the Exponential Growth and Decay part necessary?
Please help me ASAP if you can...
Thanx.

Its the base an makes easy when u deal with differntiation and integration

 

[iKhaled]

mathematics ppl...
http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_qp_11.pdf

question 5, the 2nd part.

sin theta = 1

y 90 degrees is not included in the interval? please help me with it...​

 

[Bivek]

9709/13/O/N/10 --- qn. no. 8 (ii) , how to find the length of PQ ? plz help (how it is cos0.6 cant understand in MS) ... thank u...

 

[parthrocks]

mathematics ppl...​

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s11_qp_11.pdf​

​

question 5, the 2nd part.​

​

sin theta = 1​

​

y 90 degrees is not included in the interval? please help me with it...​

Hey bro the equation in part one
2 sin
4q + sin2q − 1 = 0.
continue solving this by replacing six^2Q as x and then u will get one general equation like this

2x^2 + x -1=0
then solve it and u will get value for x
then as u know sin^2 thita=x
replace it and then get value for thita...hope u understood!!!!
jay shree krishna!!

and then apply periodic property 180-thita
and 360+-thita

 

[Albert Einstein]

9709/13/O/N/10 --- qn. no. 8 (ii) , how to find the length of PQ ? plz help (how it is cos0.6 cant understand in MS) ... thank u...

All what u need is to understand the ground.......

 

[Arjun Dhanak]

Hi. Pls help me in integration.
How do we find this:
∫ (x^2+1)^5 dx. with limits 0 to 3.
Thanks in advance.

 

[parthrocks]

sum 1 plzz help me out!!
leadingguy
smzimran
shanky631
Amy Bloom
minato112

 

[hussamh10]

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s10_qp_11.pdf
Q1 plzz help..
explain posting 2nd time

 

[Amy Bloom]

Hi. Pls help me in integration.
How do we find this:
∫ (x^2+1)^5 dx. with limits 0 to 3.
Thanks in advance.

Hi. Hope this helps, i tried it very quickly, so check it once again.

 

[leadingguy]

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s10_qp_11.pdf
Q1 plzz help..
explain posting 2nd time

tan(pi- x) = -tanx so ans is -k.

tan(pi/2 - x) = reflection of tanx means the ans will be inverse. 1/k
it is better explained in book from pages 172-179 core maths by s.bostock and s.chandler see there for clear understanding. by means of graphs

 

[leadingguy]

sum 1 plzz help me out!!
leadingguy
smzimran
shanky631
Amy Bloom
minato112

please post the ans.

 

[iKhaled]

http://www.xtremepapers.com/papers/...S Level/Mathematics (9709)/9709_s10_qp_11.pdf
Q1 plzz help..
explain posting 2nd time

omg sorry instead of all the pi i drew change it to 1/2pi..my fauly sorry :$

i hope this will help u !

 

[Arjun Dhanak]

Hi. Hope this helps, i tried it very quickly, so check it once again.
View attachment 15379

Hey thanks for trying but that is not the answer.....
the answer is 30697.55844

 

[Abu mota]

1)simplify as far as possible:
x^-1/2+x^1/2 divided by x^1/2+x^3/2
2) solve the equation:
(10/x^2+x-6)- (4/x^2-2x)-2/x^2+3x=2/5