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Its simple! Ok, the equation that you form will be (tan^2x/3) < 1, then you take 3 to the other side making it tan^2x < 3, then you square root both sides making it tanx < (square root) 3. Then using precise angles (not exactly sure what its called) you should know that tan inverse (square root) 3 is 60 degrees, or (pie)/3. You get it? So x < ((pie)/3)how we solve tan^2???can usolve it
http://olevel.sourceforge.net/papers/9709/9709_s12_qp_11.pdf