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seventh term=a+6dHelp!!!
Find the sum of the A.P. -7-3+1+.... From the seventh to the thirtieth term inclusive.
p3?can anyone differentiate ths xy(x+y) plzz???
The sum shud b 1512 :/seventh term=a+6d
=-7+6(4)
=17
13th term=a+12d
=-7+12(4)
=41
Number tems bw 7 &13=6
sum of Ap=6/2(41+17)
=174
Hope iam right not 100% sure
Your working is right, but the Number of terms between 7 & 13 should be 7, not 6. If you use that the sum = 203 which i think is correctseventh term=a+6d
=-7+6(4)
=17
13th term=a+12d
=-7+12(4)
=41
Number tems bw 7 &13=6
sum of Ap=6/2(41+17)
=174
Hope iam right not 100% sure
Are you sure, i doubt it. Like even if you do it without using a formula (getting all the terms up to 13 and then adding from the 7th to the 13th) you won't get that answer :/The sum shud b 1512 :/
sorry my mistake i dont get how the sum be so big if u do it widout formula it doesnt come that big...Your working is right, but the Number of terms between 7 & 13 should be 7, not 6. If you use that the sum = 203 which i think is correct
Are you sure, i doubt it. Like even if you do it without using a formula (getting all the terms up to 13 and then adding from the 7th to the 13th) you won't get that answer :/
haha no need to say sorry! but i agree no way the sum is thaaaat big!sorry my mistake i dont get how the sum be so big if u do it widout formula it doesnt come that big...
whitecorp can you or someone else please explain me the M/J 2012 Paper 11 Q. no 7 b) i). Sorry no links to the papers because they are not yet uploaded in the Xtremepapers.
AcosBx+ccan sme1 help me with the cosine curves in as.like i have problms in this equation 3-4cosx.
I remember doing this question, and getting it wrong lol. Convergent means like the GP is going to a number but it never actually gets to that number, like you know when r of the GP is less than 1 and you have to find the sum to infinity, thats the number that it approaches but it will never get to that number! So basically you will say ((Second Term of GP)/(First Term of GP)) < 1 . Then you solve that equation that you get...
how we solve tan^2???can usolve itI remember doing this question, and getting it wrong lol. Convergent means like the GP is going to a number but it never actually gets to that number, like you know when r of the GP is less than 1 and you have to find the sum to infinity, thats the number that it approaches but it will never get to that number! So basically you will say ((Second Term of GP)/(First Term of GP)) < 1 . Then you solve that equation that you get...
Its simple! Ok, the equation that you form will be (tan^2x/3) < 1, then you take 3 to the other side making it tan^2x < 3, then you square root both sides making it tanx < (square root) 3. Then using precise angles (not exactly sure what its called) you should know that tan inverse (square root) 3 is 60 degrees, or (pie)/3. You get it? So x < ((pie)/3)how we solve tan^2???can usolve it
http://olevel.sourceforge.net/papers/9709/9709_s12_qp_11.pdf
yeah Thanx man i get ...Its simple! Ok, the equation that you form will be (tan^2x/3) < 1, then you take 3 to the other side making it tan^2x < 3, then you square root both sides making it tanx < (square root) 3. Then using precise angles (not exactly sure what its called) you should know that tan inverse (square root) 3 is 60 degrees, or (pie)/3. You get it? So x < ((pie)/3)
can u please post the link??i hv a ques,
its ques no 2 , nov 2011, var 11.
pls ppl tel me, tht how cn we find out tht the gradient is neg. :/
i hv seen da mark scheme but its really brief.
rep asap!
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