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Mathematics: Post your doubts here!

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Hello sir for iteration!!a doubt in my mind!!
Do we take the initial value as average suppose if the root lies between 1
6<x<9 then do we do (6+9)/2 and take 7.5 as initial value or just take 6 the starting value as initial value !!!
plz its uregent and many of my friends also have this doubt plz help sir

For iteration would can literally use any value that you want, its just that if you use a number like 100000, it will LITERALLY take you FOREVER to find the root, but if you take a number half way between 6 and 9 ---> 7.5, then you'll most likely get the root very quickly
 
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Guys need some help with these 2 things!!!!

put the into a form that can be integrated:

4(cos3x)^2

&

Find the least value of N in this equation
N = e^50ksin(0.02t) + ln125
 
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Guys need some help with these 2 things!!!!

put the into a form that can be integrated:

4(cos3x)^2

&

Find the least value of N in this equation
N = e^50ksin(0.02t) + ln125

For the former, you can rewrite 4(cos3x)^2 as 4 [ (cos6x+1)/2 ] = 2 cos6x +2
(Note this is achieved through the cosine double angle formula)

For the latter, is k a constant or variable?

Peace.
 
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For the former, you can rewrite 4(cos3x)^2 as 4 [ (cos6x+1)/2 ] = 2 cos6x +2
(Note this is achieved through the cosine double angle formula)

For the latter, is k a constant or variable?

Peace.

Sir, can u plz help me.
image.jpg image.jpg
 
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For the former, you can rewrite 4(cos3x)^2 as 4 [ (cos6x+1)/2 ] = 2 cos6x +2
(Note this is achieved through the cosine double angle formula)

For the latter, is k a constant or variable?

Peace.
Thanks 2 the first 1, as for the second one, forgot 2 say that k=0.01

By the way, where do u get the solutions that you have been posting from?
 
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Thanks 2 the first 1, as for the second one, forgot 2 say that k=0.01

By the way, where do u get the solutions that you have been posting from?

For N = e^50ksin(0.02t) + ln125 , recognising that sin (0.02t) will reside between -1 and +1 inclusive, we can surmise that
minimum value of sin (0.02t) will be exactly = -1.

Hence, minimum value of N = e^50 * (0.01)(-1) +ln 125
= -5.185 * 10^(19) (shown)

Hope this helps. Peace.
 
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