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Mathematics: Post your doubts here!

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JazakAllah ... thanks alot..... is there any specific technique for these questions or just trial and error thing? and how much formulae related to trig do we have to remember?
nah there isn't any specific technique u will just need to memorize all the trig formulas u have from ur AS level and A2 level book and practice a lot of questions on prove identity to get experienced in solving them. you only need to memorize the formulas and practice a lot to be experienced how to deal with these questions and which formulas to use.
 
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nah there isn't any specific technique u will just need to memorize all the trig formulas u have from ur AS level and A2 level book and practice a lot of questions on prove identity to get experienced in solving them. you only need to memorize the formulas and practice a lot to be experienced how to deal with these questions and which formulas to use.

but there are some formulae in the booklet too.?
 
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x7lzr.png


Please help me solve the question above (I'll appreciate a step-by-step explanation).
Thanks!
 
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x7lzr.png


Please help me solve the question above (I'll appreciate a step-by-step explanation).
Thanks!
1. convert it into this form ... (3x+1)^0.5

2. add 1 to the power... (3x+1)^1.5

3.divide the whole thing with the new power [(3x+1)^1.5] / 1.5

4. differentiate the term inside the bracket. that wud be 3

5. divide the whole term with 3.

6.[ (3x+1)^1.5] divided by [ 1.5 x 3]

7. that would make it [(3x+1)^1.5]
....................................__________ + C

..........................................4.5


8. now you put limits ... put 1 into x then put 0 into x.

then substact the X=0 term from the X=1 term

9. putting 1
[(4^1.5)] ............... [(3(0)+1)^1.5]
_______ _ _________
4.5............................... 4.5

10. (16/9) _ (2/9)

it will give you 14/9 as the final answer :)
 
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1. convert it into this form ... (3x+1)^0.5

2. add 1 to the power... (3x+1)^1.5

3.divide the whole thing with the new power [(3x+1)^1.5] / 1.5

4. differentiate the term inside the bracket. that wud be 3

5. divide the whole term with 3.

6.[ (3x+1)^1.5] divided by [ 1.5 x 3]

7. that would make it [(3x+1)^1.5]
....................................__________ + C

..........................................4.5


8. now you put limits ... put 1 into x then put 0 into x.

then substact the X=0 term from the X=1 term

9. putting 1
[(4^1.5)] ............... [(3(0)+1)^1.5]
_______ _ _________
4.5............................... 4.5

10. (16/9) _ (2/9)

it will give you 14/9 as the final answer :)
ignore the ......... it is for gap
 
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can someone please explain question 5 of this paper in FULL DETAILS!
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w06_qp_3.pdf
thank you.
this looks tough but is a peice of cake as the numbers given suggest.
i want you to ignore the ....... part. it stands for gap or space ok?

take [(1+x)^0.5] as a
take [(1-x)^0.5] as b

(a+b) (a-b)= (a^2) - (b^2)

putting back the values of a and b
[(1+x)^0.5]^2 - [(1-x)^0.5]^2



that wud give u

(1+x)-(1-x)

simplify this and you will get 2x
 
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after that its just a matter of cross multiplication

currently
(a+b)(a-b)=2x

so ..........(1).........................(a-b)
......_______......= ......._______
............ (a+b) ...................... 2x
 
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1. convert it into this form ... (3x+1)^0.5

2. add 1 to the power... (3x+1)^1.5

3.divide the whole thing with the new power [(3x+1)^1.5] / 1.5

4. differentiate the term inside the bracket. that wud be 3

5. divide the whole term with 3.

6.[ (3x+1)^1.5] divided by [ 1.5 x 3]

7. that would make it [(3x+1)^1.5]
....................................__________ + C

..........................................4.5


8. now you put limits ... put 1 into x then put 0 into x.

then substact the X=0 term from the X=1 term

9. putting 1
[(4^1.5)] ............... [(3(0)+1)^1.5]
_______ _ _________
4.5............................... 4.5

10. (16/9) _ (2/9)

it will give you 14/9 as the final answer :)

Thanks a lot.. ur amazing!

I understood fully till step 3.. but I don't get why you differentiated the term in the bracket and divided the whole term by the answer.
Secondly, in step 6, I don't understand why you multiplied 1.5 by 3.. please explain the steps 4, 5, 6 & 7.

I know I'm bothering you.. but I really need your help since I'm not very good at maths.

Thanks
Waiting for your reply..
 
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Thanks a lot.. ur amazing!

I understood fully till step 3.. but I don't get why you differentiated the term in the bracket and divided the whole term by the answer.
Secondly, in step 6, I don't understand why you multiplied 1.5 by 3.. please explain the steps 4, 5, 6 & 7.

I know I'm bothering you.. but I really need your help since I'm not very good at maths.

Thanks
Waiting for your reply..
thats a rule of integration... we add one to the power... divide the term with new power and divide it with the differential of the term
 
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Thanks a lot.. ur amazing!

I understood fully till step 3.. but I don't get why you differentiated the term in the bracket and divided the whole term by the answer.
Secondly, in step 6, I don't understand why you multiplied 1.5 by 3.. please explain the steps 4, 5, 6 & 7.

I know I'm bothering you.. but I really need your help since I'm not very good at maths.

Thanks
Waiting for your reply..
in step 6 i multiplied 1.5 by 3 becux

somethng divided by 3 divided by 1.5 can also be written as
something divided by (1.5 x3)
:)
 
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in step 6 i multiplied 1.5 by 3 becux

somethng divided by 3 divided by 1.5 can also be written as
something divided by (1.5 x3)
:)
Thank you for your reply..

I'm still confused :(
Are we dividing just the denominator by 3 or the whole term?
3/2 divided by 3 = 3/6 !
If you don't mind.. can you please please show the working..
 
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Thank you for your reply..

I'm still confused :(
Are we dividing just the denominator by 3 or the whole term?
3/2 divided by 3 = 3/6 !
If you don't mind.. can you please please show the working..
ok


lets take 9
lets take 9... 9/1.5=6 6/3=2

now the other way 1.5 x3 = 4.5
9/4.5= 2

:)
 
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how to solve circle propertise
What do you mean by that?
Are you talking about Circular measure?
If so then remember these two formula's.
For the length of arc =theeta x radius (where theeta would be in radian mode)
For area of sector = 1/2 x r^2 x theeta.
 
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