Mathematics: Post your doubts here!

[VelaneDeBeaute]

Find the definite integral of √(5x + 4) from x = 0 to x= 1

This question seems easy but I'm not able to solve it.. please help!
Thanks!

The base 5x + 4 is raised to 1/2. So simply add 1 to the power, that makes it 3/2. Divide the whole term by 3/2, and you have the intergral of √(5x + 4) as 2{(5x+4)^3/2} / 3.
Now do the limits thing.

 

[whitecorp]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s09_qp_3.pdf


Its question number 6

The parametric equations of a curve are
x = a cos3 t, y = a sin3 t,
where a is a positive constant and 0 < t < pie/2
(i) Express dydx in terms of t. [3]
(ii) Show that the equation of the tangent to the curve at the point with parameter t is
x sin t + y cos t = a sin t cos t.

part 1 done.How to do part (ii) ?

whitecorp or anybody ? Thank You

For the part where you mentioned x = a cos3 t, y = a sin3 t,
is it x = a cos^3 t, y = a sin^3 t, or x = a cos(3 t) , y = a sin(3 t) ?

 

[Silent Hunter]

For the part where you mentioned x = a cos3 t, y = a sin3 t,
is it x = a cos^3 t, y = a sin^3 t, or x = a cos(3 t) , y = a sin(3 t) ?

its x = a cos^3 t, y = a sin^3 t

 

[iFuz]

I need notes for
Paper 3
- Integration by substitution
- Integration by parts
- Differential Equations
- Vectors
- Numerical solutions of equations

 

[whitecorp]

I need notes for
Paper 3
- Integration by substitution
- Integration by parts
- Differential Equations
- Vectors
- Numerical solutions of equations

You can refer to my supplementary site www.a-levelmaths.com (summaries handout section).

I have written some stuff for the first 4 topics.

Hope you will find it useful. Peace.

 

[iFuz]

You can refer to my supplementary site www.a-levelmaths.com (summaries handout section).

I have written some stuff for the first 4 topics.

Hope you will find it useful. Peace.

Thankyou Let me check these now

 

[Soldier313]

Aoa wr wb.
Can someone please help me with this? (it's urgent)

whitecorp VelaneDeBeaute Rutzaba and everyone else
Thank you.

 

[Rutzaba]

Aoa wr wb.
Can someone please help me with this? (it's urgent)View attachment 19142

whitecorp VelaneDeBeaute Rutzaba and everyone else
Thank you.

Swt heart how am i supposed to make a diagram here?
wch year is this?

 

[Soldier313]

Swt heart how am i supposed to make a diagram here?
wch year is this?

mj/12 p33
it's okay leave out the diagram, i will try that
just help me with part i) please
Thanx

 

[Rutzaba]

mj/12 p33
it's okay leave out the diagram, i will try that
just help me with part i) please
Thanx

solve em simultaneously

 

[Rutzaba]

Lets make u to be the subjct of formula ..... u=4i+w
substitute into othr eq .... (4i+w) (w)= 5
(W^2) +4iw -5=0

 

[Soldier313]

Lets make u to be the subjct of formula ..... u=4i+w
substitute into othr eq .... (4i+w) (w)= 5
(W^2) +4iw -5=0

lol hahhaa i can't believe i didn't see that! Thanx a million sis!!!

 

[Rutzaba]

lol hahhaa i can't believe i didn't see that! Thanx a million sis!!!

Np dear

 

[iKhaled]

can someone please explain question 5 of this paper in FULL DETAILS!

http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w06_qp_3.pdf

thank you.

 

[shanky631]

what is the present value of Rupee 1 to be received after 2 years compounded annually at 10%?? can someone plz solve this.

 

[shanky631]

what is the present value of Rupee 1 to be received after 2 years compounded annually at 10%?? can someone plz solve this.

whitecorp

 

[iKhaled]

can someone please explain question 5 of this paper in FULL DETAILS!
http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_w06_qp_3.pdf
thank you.

 

[Silent Hunter]

http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s11_qp_31.pdf

Q9 (i) ...... please solve anybody help ..... i just cant get the trigonometry proving thingy

 

[iKhaled]

http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s11_qp_31.pdf

Q9 (i) ...... please solve anybody help ..... i just cant get the trigonometry proving thingy

cos 4θ + 4cos 2θ = 8cos^4 θ -3

cos 4θ = 2cos^2 2θ -1 ( double angle formulae )

2cos^2 2θ - 1 + 4cos 2θ
2 (cos 2θ)(cos2θ) - 1 + 4cos 2θ

use the double angle formula again cos 2θ = 2cos^2 θ -1

2(2cos^2 θ -1)(2cos^2 θ -1 )-1 +4(2cos^2 θ-1)
2(4cos^4 θ -4cos^2 θ +1)-1 +8cos^2θ -4

expand the brackets and cancel stuff u will end up with 8cos^4 θ -3

 

[Silent Hunter]

cos 4θ + 4cos 2θ = 8cos^4 θ -3

cos 4θ = 2cos^2 2θ -1 ( double angle formulae )

2cos^2 2θ - 1 + 4cos 2θ
2 (cos 2θ)(cos2θ) - 1 + 4cos 2θ

use the double angle formula again cos 2θ = 2cos^2 θ -1

2(2cos^2 θ -1)(2cos^2 θ -1 )-1 +4(2cos^2 θ-1)
2(4cos^4 θ -4cos^2 θ +1)-1 +8cos^2θ -4

expand the brackets and cancel stuff u will end up with 8cos^4 θ -3

JazakAllah ... thanks alot..... is there any specific technique for these questions or just trial and error thing? and how much formulae related to trig do we have to remember?