Mathematics: Post your doubts here!

[destined007]

http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_s07_qp_6.pdf
http://www.xtremepapers.com/CIE/Interna ... 7_ms_6.pdf
in this the 7th question says that peppers r taken witout replacement but tat means teh method shown in mark scheme is wrong rite ??? i mean wat wud be the diff in formula of 7 i) if it was taken wit replacement ??!

The markiing scheme is correct. They have done in term of combination. You can also do using probability.
P(different)= R,G,Y x 6
3/12 x 4/11 x 5/10 x 6= 3/11

P(2 G)= G,G,O x 3 where O is any other
=4/12 x 3/11 x 8/10 x 3= 12/55

now do for others.

 

[destined007]

http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_w04_qp_4.pdf please help me with number 2 mechanics.. urgent

 

[IgoforA]

http://www.xtremepapers.com/CIE/Interna ... _qp_42.pdf help me with no 4 part 3.. thank you

 

[hassam]

 

[XPFMember]

Assalamoalaikum!


You find the x^2 of all observations and add them all! and then find sd using that eqn!

 

[destined007]

http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_w09_qp_42.pdf help me with no 4 part 3.. thank you

 

[IgoforA]

http://www.xtremepapers.com/CIE/Interna ... _qp_43.pdf can you help me with q3.. urgent help needed. tq

 

[sea_princess]

i) 2Tcos30 =3square root 3
cos 30= (square root 3)/2
so T*square root 3 = 3 square root 3
T=3
ii)resolve forces on Q
Normal component= 10m cos 30
so you have : 3=0.75* (10m cos30)+10m sin 30
11.5m =3
m= 0.261 kg

 

[sagystu]

could some one please help me when a particle is throughen and 4 sec. later a particle is thrown why do we deduct 4s from time of secound particle to make do kinamatics ?
particle 1 t=t
particle 2 t=t-4.................. why not t+4 as it was thrown 4 sec later

 

[Abdulrab]

but the question says that the time when their height is same so if the 2nd particle is thrown 4 sec later than the first particle so it will reach the height of the first particle in 4 s later than the first particle thats why we deduct 4 sec from the time of particle 2 !!! i hope that i made it clear if i helped please hit thanks !!

 

[IgoforA]

http://www.xtremepapers.com/CIE/Interna ... 5_qp_4.pdf can someone help me with no 3?.. i'm quite weak at this type of question... any notes and advices would be useful!.. thank you

 

[IgoforA]

Help needed.. urgent

 

[IgoforA]

And i need tips on drawing s-t and v-t graph?? please help... urgent

 

[IgoforA]

c'mon please.. gonna have the exam in 13 hrs time

 

[destined007]

http://www.xtremepapers.com/CIE/International%20A%20And%20AS%20Level/9709%20-%20Mathematics/9709_w05_qp_4.pdf can someone help me with no 3?.. i'm quite weak at this type of question... any notes and advices would be useful!.. thank you

 

[destined007]

And i need tips on drawing s-t and v-t graph?? please help... urgent

Well you need to have a good concept.

 

[IgoforA]

http://www.xtremepapers.com/CIE/Interna ... _qp_41.pdf how about this isn't it same but different method??

 

[notgeek]

listen jus think of it lyk this.... 0.4 sec later,, it means its 0.4 sec slower than P... wen P is at 0.4 second distance.. Q is about 2 start only...

 

[IgoforA]

i mean the previous one was question number 3... hah sorry

 

[IgoforA]

http://www.xtremepapers.com/CIE/Interna ... _qp_41.pdf c'mon help me with number 3 and guidlines to answer this type of question? urgent