Mathematics: Post your doubts here!

[josephsai]

for

Assalamualikum
Can someone please help me with question 7(ii), 8(i) & 11(ii).
Thanks a bunch in advance.

SRY i thought u meant Q7i) btw for ii) i got f inverse to be-x^2 +10x -14 am nt really sure
Q8i)d^2y/dx^2= 9(3x-4)^1/2 -6
Q11(ii) dy/dx=2x(x-2) + (x-2)^2 using product rule
expand
2x^2 -4x + x^2 -4x + 4
simplify
3x^2 - 8x + 4=0
x=2/3 & x=2
therefore b=2/3

 

[tanmaydube]

Summer 11 paper 32
Question 4 i)
Please help.

Thank you!

 

[littlecloud11]

Summer 11 paper 32
Question 4 i)
Please help.

Thank you!

OCT is a right-angled triangle with ∠OCT being 90 degree.
So, tan x = CT/r
CT =r tanx
Area of triangle = 1/2 * base* height =1/2 *r * rtanx
Area of shaded region = 1/2 r^2 tanx- 1/2 r^2 x
Area of semi-circle = 1/2* r^2* π
Area of semi-circle= area of shaded region
1/2*r^2* π = 1/2 * r^2* (tanx -x)
After canceling from both sides you get
π + x= tanx

 

[Alice123]

Summer 11 paper 32
Question 4 i)
Please help.

Thank you!

If u dnt understand feel free to ask

 

[Alice123]

Aoa anybody got some good notes according to the syllabus (M1) ? need them urgent?

JazakAllah

http://www.examsolutions.net/maths-revision/syllabuses/CIE/period-1/M1/module.php
hope this helps

 

[tanmaydube]

Thanks a lot Alice123 and littlecloud11 ! You guys are awesome!!

 

[tanmaydube]

Help Again please Summer 2011 paper 32
Question 6 i)

Question 6 ii) (if possible)
Thank You

 

[Alice123]

Help Again please Summer 2011 paper 32
Question 6 i)

Question 6 ii) (if possible)
Thank You

https://www.xtremepapers.com/community/attachments/maths-solve-q6-001-jpg.2196/

 

[Ammirul Shafiq]

How to solve these questions. 33/M/J/12

Q3) x= sin 2θ - θ, y= cos 2θ + 2 sinθ

show that dy/dx = 2 cosθ/1+2 sinθ

Q6)

It is given tan 3x = k tan x, where k is constant and tan x not equal to 0

i) By first expanding tan(2x+x), show that

(3k-1) tan^2x = k-3


tq

 

[tanmaydube]

Thanks again for the help Alice123 !

 

[Tabi Sheikh]

help plzzzzz!!!!!!!!!!!!!!!!!!
papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s03_qp_1.pdf
Question #1

 

[Ammirul Shafiq]

help plzzzzz!!!!!!!!!!!!!!!!!!
papers.xtremepapers.com/CIE/Cambridge%20International%20A%20and%20AS%20Level/Mathematics%20(9709)/9709_s03_qp_1.pdf
Question #1

= Factorise it to get 2x ( 1- 1/2x^2)
= (2x)^5 (1+ 5C1 (-1/2x^2) + 5C2 (-1/2x^2)^2 + 5C3 (-1/2x^2)^3+............)
(32x^5) x (-10/8x^6) = -40/x

* x^5/x^6 = 1/x.

So, coefficient of 1/x is -40.

 

[Ashique]

Guys can someone please help me out in this complex number question. Question 8, part ii : http://papers.xtremepapers.com/CIE/...AS Level/Mathematics (9709)/9709_s07_qp_3.pdf

 

[Ahmedraza73]

Sand is poured on to a horizontal floor at a rate of 4 cm^3/s and from a pile in the shape of a circular cone,of which the height is three-quarters of the radius .calculate the rate of change of the radius when the radius is 4cm.
Please can anyone solve this question for me its urgent?

 

[littlecloud11]

Guys can someone please help me out in this complex number question. Question 8, part ii : http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_s07_qp_3.pdf

 

[Ahmedraza73]

View attachment 22208

Please reply to my question

 

[Dug]

Sand is poured on to a horizontal floor at a rate of 4 cm^3/s and from a pile in the shape of a circular cone,of which the height is three-quarters of the radius .calculate the rate of change of the radius when the radius is 4cm.
Please can anyone solve this question for me its urgent?

dV/dt = 4

dr/dt = dr/dV x dV/dt

To find dr/dV, we need an equation connecting V and r.

Volume of a cone = (1/3)πr^2 h

In the question, we are told height is three-quarters of the radius, therefore replacing 'h' by (3/4)r :

V= (1/3)πr^2 (3r/4)
V =1/4 πr^3

dV/dr = (3/4)πr^2
dr/dV = 4/3(πr^2)

dr/dt = dr/dV x dV/dt
dr/dt = [4/3(πr^2)] x 4
dr/dt = 16/3πr^2

When r = 4,
dr/dt = 16/3π(4)^2
dr/dt = (1/3)π cms-1

 

[littlecloud11]

Sand is poured on to a horizontal floor at a rate of 4 cm^3/s and from a pile in the shape of a circular cone,of which the height is three-quarters of the radius .calculate the rate of change of the radius when the radius is 4cm.
Please can anyone solve this question for me its urgent?

Formula for volume of a cone is (1/3)(pi)(r^2)(h)
You're given that h = 3r/4 so the formula becomes (1/4)(pi)(r^3)
V = (1/4) πr^3
dV/dr = (3/4) πr^2
dV/dt = dV/dr * dr/dt
4 = (3/4) πr^2 * dr/dt
4 = (3/4) π (4)^2 * dr/dt
cross-multiply and you get-
dr/dt = 1/3π cm/s

 

[Nab900]

salam

can someone explain me question 4(ii) from may june 2012
http://papers.xtremepapers.com/CIE/...S Level/Mathematics (9709)/9709_s12_qp_31.pdf

The complex number u is defined by u =((1+2i)^2)/(2+i)

(i) Without using a calculator and showing your working, express u in the form x + iy, where x and y are real.
(ii) Sketch an Argand diagram showing the locus of the complex number Z such that |Z− u| = |u|.

 

[Shreeram]

Assalamoalaikum!!
Guys please help me out with equilibrium of a rigid body for mechanics paper 5. i need it as soon as possible as im wiriting this year may... thanks a lot in advance