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Mathematics: Post your doubts here!

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leosco1995

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14lk47p.jpg


Just can't seem to get any of the answers right.. even though I think I know what I'm doing. Help would be appreciated with both parts.
 
Dug

Dug

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tanmaydube said:
View attachment 22703

Help again, stuck at the first part!!!
Click to expand...

y = sin³2x cos³2x

A = ⌡sin³2x cos³2x dx

u = sin2x
du/dx = 2cos2x
dx = du/2cos2x

A = ⌡sin³2x cos³2x du/2cos2x
A = ⌡sin³2x (cos²2x)(cos2x) du/2cos2x
A = ⌡sin³2x cos²2x du/2
A = ½ ⌡sin³2x (1 - sin²2x) du
A = ½ ⌡u³ (1 - u²) du
A = ½ ⌡u³ - u^5 du
A = ½ (u^4/4 - u^6/6)

For limits, set y = 0
sin³2x cos³2x = 0

For this function to be zero,
sin³2x = 0 or cos³2x = 0
x = 0, 45

Put these values in u = sin2x and we get the limits 0 and 1.

A = ½ (1/4 - 1/6)
A = 1/24
 
S

sk8rchick

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hey guys am new to this so plzz help!
i need igcse o level 2010 papers any one know where i can get them.. plzz help me!!
 
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sk8rchick

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guy i need help with paper 1 2010 here's the paper i need help in question no. 13 any one plzz help ASAP
 

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sk8rchick

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thnaks but i want edexcel igce 2010 papers if u have plzzz help me with it.. thanks for this one it was very usefull:)
 
Rutzaba

Rutzaba

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i think i have been ignoring this thread badly... lets divide the ques to be done so that two of us are not solving the same question and end up ignoring another...
 
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