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Mathematics: Post your doubts here!

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can anyone solve this question (9-x^2) given the limits from 0 to 3 solve this tell me why the answer is 18
 
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I am assuming integrate?
(9-x^2) limits 3-0
Integral>9-x^2
9x-x^3/3
[9(3)-(3)^3/3] - [9(0) - 0^3/3]
=27 - 9
=18

for M1 ... eg when a lorry comes DOWN a hill ... how do we now if its gain/loss in kinetic energy ... when speed at top is given only ?????
ANY ONE
 
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Mechanics problem:
Q: A particle is moving along a straight line with constant acceleration. In an interval of T sec ot moves D meters; in the next interval of 3T sec it moves 9D meters. How far does it move in a further interval of T seconds ?
Answer 5D.
Your help will be much appreciated.
 

Dug

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Fatima18

S03 qp 6
Q6 iii

P(G) = 17/42

They are asking for the probability of choosing a house where a parent lives, such that a grandparent is already chosen.

P(H|G) = P(H1|G) + P(H2|G)

P(H1|G) = P(H1∩G)/P(G) = [(1/3)(2/7)]/(17/42) = 4/17

P(H2|G) = P(H2∩G)/P(G) = [(1/3)(3/7)]/(17/42) = 6/17

P(H|G) = 10/17

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w07 qp 6
Q7

ii)

P(RB) = P(W And R) + P(R And R)

= (1/6)(7/10) + (5/6)(8/10)

= 47/60

iii)

P(RA|RB) = P(RA∩RB)/P(RB)

= (2/3)/(47/60)
 

Dug

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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w12_qp_63.pdf

can anyone plz solve Q 2, Q5 (iii) and 6n(ii) n (iii) please

Q2

To solve for the three unknowns, we need to construct three equations using the data provided.

ΣP(X=x) = 1
p + q + r + 0.4 = 1 --- (i)

E(X) = 2.3
-3p + 2r +1.6 = 2.3 --- (ii)

Var(X) = 3.01
9p + 4r + 6.4 - 2.3² = 3.01 --- (iii)

I will leave the arithmetic to you.

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Q5 iii

P(87 < X < k) = 0.3

P[(k - 82)/√126] - P[(87 - 82)/√126] = 0.3

Let t = (k - 82)/√126

Φ(t) - Φ(0.445) = 0.3

Φ(t) = 0.9718

Φ(t) = Φ(1.978)

t = 1.978

(k - 82)/√126 = 1.978

k = 104

-------------

I don't understand what you wrote next...
 

Dug

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http://papers.xtremepapers.com/CIE/Cambridge International A and AS Level/Mathematics (9709)/9709_w09_qp_61.pdf

Q5 a(ii) b(ii) and Q6

Q5

a. ii)

5 _ _ _

No. of arrangements = 6³ = 216

b. ii)

n(B) = 6

n(G) = 8

If the cousins are in, 3 boys are already selected. The number of ways to select the remaining team is 11C2.

If the cousins are out, we need to select 5 students for the team which is simply 11C5.

No. of ways = 11C2 + 11C5 = 517
 
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for M1 ... eg when a lorry comes DOWN a hill ... how do we now if its gain/loss in kinetic energy ... when speed at top is given only ?????
ANY ONE

Don't have M1. I don't know how it will be solved but.. If you know the speed as well as the height of the hill .. Potential energy changes into kinetic..

mgh = 1/2*mv^2
2gh=v^2
v=√(2gh)

Don't Have M1 so I don't really know how it will be solved...
 
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